In a period of 9.00 s, 5.00 × 1023 nitrogen molecules strike a wall of area 5.80 cm². Assume the molecules move with a speed of 340 m/s and strike the wall head-on in elastic collisions. What is the-26 kg.pressure exerted on the wall? Note: The mass of one N, molecule is 4.65 x 103.513Calculate the momentum change in each second and use the impulse-momentum theorem to relate the momentum change to the average force between the wall and the nitrogen in order to find thepressure. kPaNeed Help?Read ItMaster It

Solution:-Given thattime (∆t)=9 sNumber of molecules (N)=5×1023Area (A)=5.8 cm2=5.8×10-4 m2Initial…

Answered: In a period of 9.00 s, 5.00 x 1023…

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