In a newspaper, it was reported that yearly robberies in Springfield were down 50% to 93 in 2013 from 2012. How many robberies were there in Springfield in 2012?

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem Statement**

In a newspaper, it was reported that yearly robberies in Springfield were down 50% to 93 in 2013 from 2012. How many robberies were there in Springfield in 2012?

**Solution**

To calculate the number of robberies in Springfield in 2012, recognize that the drop from 2012 to 2013 is 50%. If 93 robberies represent the remaining 50%, the number of robberies in 2012 can be calculated as follows:

Let \( x \) be the number of robberies in 2012.

Given: 
\[ 0.5 \times x = 93 \]

Solve for \( x \):
\[ x = \frac{93}{0.5} \]
\[ x = 186 \]

Therefore, there were 186 robberies in Springfield in 2012. 

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Transcribed Image Text:**Problem Statement** In a newspaper, it was reported that yearly robberies in Springfield were down 50% to 93 in 2013 from 2012. How many robberies were there in Springfield in 2012? **Solution** To calculate the number of robberies in Springfield in 2012, recognize that the drop from 2012 to 2013 is 50%. If 93 robberies represent the remaining 50%, the number of robberies in 2012 can be calculated as follows: Let \( x \) be the number of robberies in 2012. Given: \[ 0.5 \times x = 93 \] Solve for \( x \): \[ x = \frac{93}{0.5} \] \[ x = 186 \] Therefore, there were 186 robberies in Springfield in 2012. **Interactive Component** - Input Field: [Answer: _______] - Submit Button: [Submit Answer] **Attempts Remaining** Attempt 2 out of 2
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