In a model containing two variables X and Y, where X is a positive continuous value and Y is binary integer, we wish to include the constraint that Y becomes 1 when X > 20. There is a cost attached to Y in the objective function, so it would stay at 0 unless forced to be 1. The correct way to model this constraint as a linear relationship is: ○ (X-20) (1-Y) ≥0 XY ≥ 20 OY (X-20) where M is a sufficiently large positive number. O (X-20) (Y-1)=0 O Y=IF(X > 20,1,0) OY≥

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter9: Quadratic Functions And Equations
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In a model containing two variables X and Y, where X is a positive continuous value and Y
is binary integer, we wish to include the constraint that Y becomes 1 when X > 20. There is
a cost attached to Y in the objective function, so it would stay at 0 unless forced to be 1.
The correct way to model this constraint as a linear relationship is:
○ (X-20) (1-Y) ≥0
XY ≥ 20
OY
(X-20) where M is a sufficiently large positive number.
O (X-20) (Y-1)=0
O Y=IF(X > 20,1,0)
OY≥
Transcribed Image Text:In a model containing two variables X and Y, where X is a positive continuous value and Y is binary integer, we wish to include the constraint that Y becomes 1 when X > 20. There is a cost attached to Y in the objective function, so it would stay at 0 unless forced to be 1. The correct way to model this constraint as a linear relationship is: ○ (X-20) (1-Y) ≥0 XY ≥ 20 OY (X-20) where M is a sufficiently large positive number. O (X-20) (Y-1)=0 O Y=IF(X > 20,1,0) OY≥
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