**Understanding the Freezing Point Depression Method to Determine Molecular Weight**The freezing point of benzene, \( \text{C}_6\text{H}_6 \), is \( 5.500 \, ^\circ \text{C} \) at 1 atmosphere. The cryoscopic constant (\(K_f\)) for benzene is \(5.12 \, ^\circ \text{C/m}\).In a laboratory experiment, students synthesized a new compound and found that when \(10.17\) grams of the compound were dissolved in \(267.9\) grams of benzene, the solution began to freeze at \(4.952 \, ^\circ \text{C}\). The compound was also found to be nonvolatile and a non-electrolyte.**Question:**What is the molecular weight determined for this compound?**Details:**- Mass of compound: \(10.17 \, \text{g}\)- Mass of benzene: \(267.9 \, \text{g}\)- Freezing point of pure benzene: \(5.500 \, ^\circ \text{C}\)- Freezing point of solution: \(4.952 \, ^\circ \text{C}\)- Cryoscopic constant (\(K_f\)) of benzene: \(5.12 \, ^\circ \text{C/m}\)**Steps to Solve the Problem:**1. Calculate the freezing point depression (ΔTf): \[ \Delta T_f = T_f^\circ - T_f \]where:\[ T_f^\circ \] = freezing point of the pure solvent \[ (5.500\, ^\circ\text{C}) \]\[ T_f \] = freezing point of the solution \[ (4.952\, ^\circ\text{C}) \]2. Use the equation for freezing point depression:\[ \Delta T_f = K_f \cdot m \]where:\[ K_f \] = cryoscopic constant \( (5.12\, ^\circ \text{C/m}) \)\[ m \] = molality of the solution \(\left(\text{moles of solute} / \text{kg of solvent}\right)\)3. Calculate the molality (m) of the solution:\[ m = \frac{\Delta T_f}{K_f}

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In a laboratory experiment, students synthesized a new compound and found that when 10.17 grams of the compound were dissolved in 267.9 grams of benzene, the solution began to freeze at 4.952 °C. The compound was also found to be nonvolatile and a non-electrolyte.

In a laboratory experiment, students synthesized a new compound and found that when 10.17 grams of the compound were dissolved in 267.9 grams of benzene, the solution began to freeze at 4.952 °C. The compound was also found to be nonvolatile and a non-electrolyte.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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