In a group of girls there are 10 girls with blue eyes, 12 girls with brown eyes and 6 girls with green eyes. In a group of boys there are 11 boys with blue eyes, 9 boys with brown eyes and 7 boys with green eyes. What is the probability of getting both a boy and a girl with blue eyes?

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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In a group of girls there are 10 girls with blue eyes, 12 girls with brown eyes and 6 girls with green eyes. In a group of boys there are 11 boys with blue eyes, 9 boys with brown eyes and 7 boys with green eyes. What is the probability of getting both a boy and a girl with blue eyes?
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Step 1

Given:

The number of girls with blue eyes are 10.

The number of girls with brown eyes are 12.

The number of girls with green eyes are 6.

The total number of girls are N=10+12+6=28.

The number of boys with blue eyes are 11.

The number of boys with brown eyes are 9.

The number of boys with green eyes are 7.

The total number of boys are M=11+9+7=27.

Define events:

Let G be the event representing the girls.

Let B be the event representing the boys.

Let E be the event representing the blue eyes.

So,

n(BE)=11.

n(GE)=10.

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