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In a DNA molecule, the base pair adenine and thymine is held together by two hydrogen bonds. Let's model one of these hydrogen bonds as four point charges arranged along a straight line. Using the information in the figure, calculate the magnitude of the net electric force exerted by one base on the other. N 91 92 93 94 ... 0.120 nm 0.120 nm 0.180 nm Adenine Thymine where q1 = -0.170e, q2 = +0.170e, q3 = -0.270e, and q4 = +0.270e. IN

In a DNA molecule, the base pair adenine and thymine is held together by two hydrogen bonds. Let's model one of these hydrogen bonds as four point charges arranged along a straight line. Using the information in the figure, calculate the magnitude of the net electric force exerted by one base on the other. N 91 92 93 94 ... 0.120 nm 0.120 nm 0.180 nm Adenine Thymine where q1 = -0.170e, q2 = +0.170e, q3 = -0.270e, and q4 = +0.270e. IN

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In a DNA molecule, the base pair adenine and thymine is held together by two hydrogen bonds. Let’s model one of these hydrogen bonds as four point charges arranged along a straight line. Using the information in the figure, calculate the magnitude of the net electric force exerted by one base on the other. **Figure Explanation:** - There are four point charges aligned linearly, representing the hydrogen bond between adenine and thymine. - The charges are represented as follows: - \( q_1 \) is located on nitrogen (N) on the adenine side. - \( q_2 \) is located on hydrogen (H) on the adenine side. - \( q_3 \) is located on oxygen (O) on the thymine side. - \( q_4 \) is located on carbon (C) on the thymine side. **Distances:** - The distance between \( q_1 \) and \( q_2 \) is 0.120 nm. - The distance between \( q_2 \) and \( q_3 \) is 0.180 nm. - The distance between \( q_3 \) and \( q_4 \) is 0.120 nm. **Charges:** - \( q_1 = -0.170e \) - \( q_2 = +0.170e \) - \( q_3 = -0.270e \) - \( q_4 = +0.270e \) There is a box labeled “N” for the calculation of the net electric force magnitude. To calculate the net electric force, you would apply Coulomb's Law to each pair of charges and sum the vector forces, accounting for direction and distance.
Transcribed Image Text:In a DNA molecule, the base pair adenine and thymine is held together by two hydrogen bonds. Let’s model one of these hydrogen bonds as four point charges arranged along a straight line. Using the information in the figure, calculate the magnitude of the net electric force exerted by one base on the other. **Figure Explanation:** - There are four point charges aligned linearly, representing the hydrogen bond between adenine and thymine. - The charges are represented as follows: - \( q_1 \) is located on nitrogen (N) on the adenine side. - \( q_2 \) is located on hydrogen (H) on the adenine side. - \( q_3 \) is located on oxygen (O) on the thymine side. - \( q_4 \) is located on carbon (C) on the thymine side. **Distances:** - The distance between \( q_1 \) and \( q_2 \) is 0.120 nm. - The distance between \( q_2 \) and \( q_3 \) is 0.180 nm. - The distance between \( q_3 \) and \( q_4 \) is 0.120 nm. **Charges:** - \( q_1 = -0.170e \) - \( q_2 = +0.170e \) - \( q_3 = -0.270e \) - \( q_4 = +0.270e \) There is a box labeled “N” for the calculation of the net electric force magnitude. To calculate the net electric force, you would apply Coulomb's Law to each pair of charges and sum the vector forces, accounting for direction and distance.
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