In a computer with a 32-bit data-bus, how many 4-bit wide memory components are used? the answer to this part is 32/4 = 8 components (2-bit wide) I need the answer to part two, please If the size of each 4-bit memory component is 4 x n cells where n = 1G (i.e., 4 x n uniquely addressable locations-n: row, 4:2 column/width), what is the total capacity of the memory system? Show your answer in power of 2. (hint: 1000 ~ 210)

In a computer with a 32-bit data-bus, how many 4-bit wide memory components are used? the answer to this part is 32/4 = 8 components (2-bit wide) I need the answer to part two, please If the size of each 4-bit memory component is 4 x n cells where n = 1G (i.e., 4 x n uniquely addressable locations-n: row, 4:2 column/width), what is the total capacity of the memory system? Show your answer in power of 2. (hint: 1000 ~ 210)

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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