In a certain year, 23.5% of all light vehicles were light trucks, 7.0% were SUVs, and 69.5% were cars. The probability that a severe side-impact crash would prove deadly to a driver depended on the type of vehicle he or she was driving at the time, as shown in the table.

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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In a certain year, 23.5% of all light vehicles were light trucks, 7.0% were SUVs, and 69.5% were cars. The probability that a severe side-impact crash would prove deadly to a driver depended on the type of vehicle he or she was driving at the time, as shown in the table.
Light Truck 0.210
SUV 0.371
Car 1.000
What is the probability that the victim of a deadly side-impact accident was driving a car? HINT [See Example 3.] (Round your answer to four decimal places.)
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Given data:

 


The given percentage of light trucks is P(T)=23.5%=0.235.
The given percentage of SUVs is P(S)=7%=0.07.
The given percentage of cars is P(C)=69.5%=0.695.
The probability of an accident while driving a light truck is P(A/T)=0.210.
The probability of an accident while driving an SUV is P(A/S)=0.371.
The probability of an accident while driving a car is P(A/C)=1.000.
 


The expression for the probability that the victim of an accident was driving a car is,
P(C/A)=P(A/C)P(C)P(T)P(A/T)+P(S)P(A/S)+P(A/C)P(C)
 

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