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In a certain region where the relative permittivity is 2.4, D = 2ax - 4ay+5a-nc/m². Find: (2ax-4ay+5a₂)x 10-⁹ (2.4) (8.85 x 10-12) a) b) E =94ax 188ay +235a₂ V/m (2ar-4ay+5a₂) × 10-⁹ P=D-E0E = eoE(ER 1) : = 1.2ax -2.3ay + 2.9a₂ nC/m² c) |VV| |E| = [(94.1)2+(188)2 + (235)211/2 = 315 V/m -(2.4-1) 2.4

In a certain region where the relative permittivity is 2.4, D = 2ax - 4ay+5a-nc/m². Find: (2ax-4ay+5a₂)x 10-⁹ (2.4) (8.85 x 10-12) a) b) E =94ax 188ay +235a₂ V/m (2ar-4ay+5a₂) × 10-⁹ P=D-E0E = eoE(ER 1) : = 1.2ax -2.3ay + 2.9a₂ nC/m² c) |VV| |E| = [(94.1)2+(188)2 + (235)211/2 = 315 V/m -(2.4-1) 2.4

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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electromagnetic field)I want a detailed solution because my teacher changes the numbers. I want a detailed solution. Understand the solution
Example In a certain region where the relative permittivity is 2.4, D = 2ax - 4ay + 5a-nc/m². Find: (2ax-4ay+5a₂) × 10-⁹ (2.4) (8.85 x 10-12) a) b) D E= = =94ax - 188ay + 235a₂ V/m c) (2a-4ay+5a₂) × 10-⁹ P = D-E0E = = EoE(ER-1)= = 1.2ax -2.3ay + 2.9a₂ nC/m² |VV| = |E| = [(94.1)2 + (188)2 + (235)211/2 = 315 V/m -(2.4-1) 2.4
Transcribed Image Text:Example In a certain region where the relative permittivity is 2.4, D = 2ax - 4ay + 5a-nc/m². Find: (2ax-4ay+5a₂) × 10-⁹ (2.4) (8.85 x 10-12) a) b) D E= = =94ax - 188ay + 235a₂ V/m c) (2a-4ay+5a₂) × 10-⁹ P = D-E0E = = EoE(ER-1)= = 1.2ax -2.3ay + 2.9a₂ nC/m² |VV| = |E| = [(94.1)2 + (188)2 + (235)211/2 = 315 V/m -(2.4-1) 2.4
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