In a certain experiment 7.50 mile of NH3 was placed in an empty 1.0 liter flask at 900C. After equilibrium was reached, 0.50 mile of N2 was found to be in the flask (along with other gases). Calculate the [NH3] and [H2] at equilibrium and the numerical value of Kc. 2NH3 (g) = N2(g) + 3H2(g)
In a certain experiment 7.50 mile of NH3 was placed in an empty 1.0 liter flask at 900C. After equilibrium was reached, 0.50 mile of N2 was found to be in the flask (along with other gases). Calculate the [NH3] and [H2] at equilibrium and the numerical value of Kc. 2NH3 (g) = N2(g) + 3H2(g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In a certain experiment 7.50 mile of NH3 was placed in an empty 1.0 liter flask at 900C. After equilibrium was reached, 0.50 mile of N2 was found to be in the flask (along with other gases). Calculate the [NH3] and [H2] at equilibrium and the numerical value of Kc.
2NH3 (g) = N2(g) + 3H2(g)
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