In a cathode-ray tube (CRT), an electron travels in a vacuum and enters a region between two "deflection" plates which have equal and opposite charges. The dimensions of each plate are L = 12 cm by d = 3 cm, and the gap between them is h = 2.5 mm. (Note: the diagram is not drawn to scale and the direction of the electric field may not be correct, depending on your randomization.) During a 0.001 s interval while it is between the plates, the change of the momentum of the electron Ap is < 0, 8.00e-17, 0 > kg m/s. What is the electric field between the plates? Hint: remember the Momentum Principle (the relationship between Impulse and change in momentum.) E = N/C What is the charge (both magnitude and sign) of the upper plate? q =

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In a cathode-ray tube (CRT), an electron travels in a vacuum and enters a region between two "deflection" plates which have equal and opposite charges. The dimensions of each plate are L = 12 cm by d = 3 cm, and the
gap between them is h = 2.5 mm. (Note: the diagram is not drawn to scale and the direction of the electric field may not be correct, depending on your randomization.)
During a 0.001 s interval while it is between the plates, the change of the momentum of the electron Ap is < 0, 8.00e-17, 0 > kg m/s.
What is the electric field between the plates?
Hint: remember the Momentum Principle (the relationship between Impulse and change in momentum.)
E =
N/C
What is the charge (both magnitude and sign) of the upper plate?
q =
Transcribed Image Text:In a cathode-ray tube (CRT), an electron travels in a vacuum and enters a region between two "deflection" plates which have equal and opposite charges. The dimensions of each plate are L = 12 cm by d = 3 cm, and the gap between them is h = 2.5 mm. (Note: the diagram is not drawn to scale and the direction of the electric field may not be correct, depending on your randomization.) During a 0.001 s interval while it is between the plates, the change of the momentum of the electron Ap is < 0, 8.00e-17, 0 > kg m/s. What is the electric field between the plates? Hint: remember the Momentum Principle (the relationship between Impulse and change in momentum.) E = N/C What is the charge (both magnitude and sign) of the upper plate? q =
Expert Solution
Step 1

Given data, 

L = 12 cm = 0.12 m 

d = 3 cm = 0.03 m 

t = 0.001 s 

p=<0,8.00 x 10-17,0>

The force of the elctron is qE (not considering weight) and that's equal to the rate of change of momentum E=1Qptwhere, Q is the electron's chargeE=1-1.6 x 10-198 x 10-170.001=<0,-5 x 105,0>E=<0,-5 x 105N/C,0>  

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