In a business, the Chief Executive Officer wants to know if his workers are for or against mandatory vaccinations. A random sample of 200 workers was taken and the results are shown in the MINITAB output below Expected counts are printed below observed counts Managers Team leaders Employees Total 17 22 15 Approve 21.330 17.820 14.850 54 34 25 14 Against 28.835 24.090 20.075 73 28 19 26 No Opinion 28.835 24.090 20.075 73 Total 79 66 55 200 Chi-są = 0.878992 + 0.980494 + 0.001515 + 0.925168+ 0.034375 + 1.838387 + 0.02418 + 1.075471 + 1.74874 =7.507306 i. What is the value of the degree of freedom for this test? ii. What is the p-value for this test? iii. Carefully define the null and alternative hypotheses of the x test underlying the generation of the above table. iv. Using a = 10%, what is the conclusion of this test? Give reasons for your answer. marks

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