In a 6.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.45 bar, how many moles of steam are in the cooker? (R = 0.08314 L-bar/mol-K)

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Chapter1: Chemical Foundations
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#### Question 12 of 12

**Problem Statement:**
In a 6.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.45 bar, how many moles of steam are in the cooker? (Given: \( R = 0.08314 \, \text{L·bar/mol·K} \))

**Concepts Involved:**
- **Ideal Gas Law**: The problem requires understanding the Ideal Gas Law, expressed as \( PV = nRT \), where:
  - \( P \) = pressure in bar.
  - \( V \) = volume in liters.
  - \( n \) = number of moles of the gas.
  - \( R \) = ideal gas constant (\(0.08314 \, \text{L·bar/mol·K}\)).
  - \( T \) = temperature in Kelvin (K).

**Approach:**
1. **Convert Temperature to Kelvin:**
   - \( T_{\text{K}} = 115 + 273.15 = 388.15 \, \text{K} \)

2. **Apply the Ideal Gas Law:**
   - Rearrange the formula to solve for \( n \) (moles of steam):
   \[
   n = \frac{PV}{RT}
   \]
   - Substitute the known values into the equation:
   \[
   n = \frac{(3.45 \, \text{bar})(6.00 \, \text{L})}{(0.08314 \, \text{L·bar/mol·K})(388.15 \, \text{K})}
   \]

**Calculation:**
- Perform the calculation to find the value of \( n \), representing the number of moles of steam.

#### Note:
There are no graphs or diagrams associated with this question. The focus is on applying the Ideal Gas Law to solve for the number of moles of gas in a given system.
Transcribed Image Text:### Educational Content #### Question 12 of 12 **Problem Statement:** In a 6.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.45 bar, how many moles of steam are in the cooker? (Given: \( R = 0.08314 \, \text{L·bar/mol·K} \)) **Concepts Involved:** - **Ideal Gas Law**: The problem requires understanding the Ideal Gas Law, expressed as \( PV = nRT \), where: - \( P \) = pressure in bar. - \( V \) = volume in liters. - \( n \) = number of moles of the gas. - \( R \) = ideal gas constant (\(0.08314 \, \text{L·bar/mol·K}\)). - \( T \) = temperature in Kelvin (K). **Approach:** 1. **Convert Temperature to Kelvin:** - \( T_{\text{K}} = 115 + 273.15 = 388.15 \, \text{K} \) 2. **Apply the Ideal Gas Law:** - Rearrange the formula to solve for \( n \) (moles of steam): \[ n = \frac{PV}{RT} \] - Substitute the known values into the equation: \[ n = \frac{(3.45 \, \text{bar})(6.00 \, \text{L})}{(0.08314 \, \text{L·bar/mol·K})(388.15 \, \text{K})} \] **Calculation:** - Perform the calculation to find the value of \( n \), representing the number of moles of steam. #### Note: There are no graphs or diagrams associated with this question. The focus is on applying the Ideal Gas Law to solve for the number of moles of gas in a given system.
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