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In a 24-hour period, the water depth in a harbour changes from a minimum of 3/2 m at 2 am to a maximum of 7 at 8:00 am. Which of the following equations best describes the relationship between the depth of the water and time in the 24-hour time period? Od=-1 cos (π (t-2)) + ¹/7 d=cos (π (t-2)) + 1/7/ d = sin (π (t-2)) + ¹/7 d = sin(π (t− 2)) +

In a 24-hour period, the water depth in a harbour changes from a minimum of 3/2 m at 2 am to a maximum of 7 at 8:00 am. Which of the following equations best describes the relationship between the depth of the water and time in the 24-hour time period? Od=-1 cos (π (t-2)) + ¹/7 d=cos (π (t-2)) + 1/7/ d = sin (π (t-2)) + ¹/7 d = sin(π (t− 2)) +

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In a 24-hour period, the water depth in a harbour changes from a minimum of 3/2 m at 2 am to a maximum of 7 at 8:00 am. Which of the following equations best describes the relationship between the depth of the water and time in the 24-hour time period? ³ (π (t− 2)) + ¹/7 d=-c COS (t− 2)) + ¹/7 d = −sin (π (t− 2)) + d= cos (π (t-2 1/ π d = sin (π (t− 2)) + 24/7
Transcribed Image Text:In a 24-hour period, the water depth in a harbour changes from a minimum of 3/2 m at 2 am to a maximum of 7 at 8:00 am. Which of the following equations best describes the relationship between the depth of the water and time in the 24-hour time period? ³ (π (t− 2)) + ¹/7 d=-c COS (t− 2)) + ¹/7 d = −sin (π (t− 2)) + d= cos (π (t-2 1/ π d = sin (π (t− 2)) + 24/7
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