In a 100-rn race, the winner is timed at 11.2 s. The second-place finisher's time Is 11.6 s. How far is the second-place finisher behind the winner when she crosses the finish line? Assume the velocity of each runner is constant throughout the race.

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Q: A car moving in a straight line starts at x = 0 at t = 0. It passes the point x = 25.0 m with a…

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Q: 43. (a) 5.32 m/s² for Laura and 3.75 m/s² for Healan (b) 10.6 m/s for Laura and 11.2 m/s for Healan…

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Q: a van travels a distance d=25.6m in the positive x direction in a time t1=23.7s, at which point it…

A: The objective of the question is to calculate the van's average velocity, acceleration during the…

Q: Velocity-Time Graph 8.0 6.0 40 2.0 0.0 -2.000 20 40 80 80 100 120 14 0 160 180 20.0 40 -80 -8.0 Time…

A: We have velocity time graph

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Q: A lion is napping in the shade as a zebra saunters by at steady 48.2 km/h. Feeling the desire for…

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Q: aylor is swimming in a race with only one lap (50m) to go. The first place swimmer is 16m ahead of…

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Q: A ball is thrown directly downward with an initial speed of 8.90 m/s, from a height of 30.5 m. After…

A: initial velocity, u = 8.9 m/s  height, h = 30.5 m

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Q: How far, in m, is the location of the beatdown from where the fart occurred?

A: we can apply Newton's equation of motion for this.

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A:

Q: While standing on a bridge 13.9 m above the ground, you drop a stone from rest. When the stone has…

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Q: A particle travels along a straight line such that in 4s it moves from an initial position SA =…

A: Calculate the total displacement of the particle. d=SC−SAd=1.75 m−1 md=0.75 m

Q: Jack and Jill exercise in a 25.0 m long swimming pool. Jack swims 9 lengths of the pool in 146.7 s…

A:

Q: A lion is napping in the shade as a zebra saunters by at steady 48.2 km/h. Feeling the desire for…

A:

Q: -vel 5. Ablue car and a red car are racing. They start in the same place.at the same time. The blue…

A: three equation of motion are v = u +at  v2 - u2 = 2as  s = ut + 0.5gt2     here  v = final velocity…

Q: A car, initially at rest, accelerates at a constant rate, 3.36 m/s2 for 32.6 seconds in a straight…

A: First we have to find  the velocity at the end of accelerationfor this we have to use first equation…