### American Spending on Halloween CostumesIn **2017**, Americans spent a record-high **$9.1 billion** on Halloween-related purchases according to The Balance website. Sample data showing the amount, in dollars, 16 adults spent on a Halloween costume are as follows:| 12 | 71 | 22 | 66 ||----|----|----|----|| 31 | 36 | 33 | 47 || 55 | 13 | 15 | 97 || 44 | 32 | 63 | 25 |#### Questions:**a. What is the estimate of the population mean amount adults spend on a Halloween costume (to 2 decimals)?**Estimated Mean: **$41.38****b. What is the sample standard deviation (to 2 decimals)?**Sample Standard Deviation: **[To be calculated]****c. Provide a 95% confidence interval estimate of the population standard deviation for the amount adults spend on a Halloween costume (to 2 decimals). Use [Table 11.1](#)**.Confidence Interval: **$[Lower Limit] \leq \sigma \leq $[Upper Limit]**### Detailed Explanation of Data PresentationThe data is presented in a tabular format showing individual spending amounts for 16 adults. These amounts are critical for calculating the sample mean and sample standard deviation, which are foundational statistics used to estimate the population parameters based on the sample data. The confidence interval provides a range within which the true population standard deviation is likely to fall, with a given level of confidence (95% in this case). This method allows for inference about the population from which the sample was taken.

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Answered: In 2017, Americans spent a record-high…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What was the age distribution of prehistoric Native Americans? Extensive anthropological studies in the southwestern United States gave the following information about prehistoric extended family group of 85 members on what is now a Native American reservation. For this community, estimate the mean age expressed in years, the sample variance, and the sample standard deviation. For the class 31 and over, use 35.5 as the class midpoint. (Round your answer to one decimal place.) Average range(years) 1-10 11-20 21-30 31 and over # of individuals 35 23 16 11 Mean=S2= S=
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