In 1939 or 1940, Emanuel Zacchini took his human-cannonball act to an extreme: After being shot from a cannon, he soared over three Ferris wheels and into a net (see the figure). Assume that he is launched with a speed of 26 m/s and at an angle of 50°. (a) Treating him as a particle, calculate his clearance over the first wheel. (b) If he reached maximum height over the middle wheel, by how much did he clear it? (c) How far from the cannon should the net's center have been positioned (neglect air drag)?

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In 1939 or 1940, Emanuel Zacchini took his human-cannonball act to an extreme: After being shot from a cannon, he soared over three Ferris wheels and into a net (see the figure). Assume that he is launched with a speed of 26 m/s and at an angle of 50°. (a) Treating him as a particle, calculate his clearance over the first wheel. (b) If he reached maximum height over the middle wheel, by how much did he clear it? (c) How far from the cannon should the net's center have been positioned (neglect air drag)?

 

 
### Projectile Motion Illustration

The provided diagram depicts a classic example of projectile motion, taking place in a setting involving three towers and a net. Key elements and annotations are as follows:

1. **Initial Velocity (\(v_0\))**: The object is launched with an initial velocity of 26 meters per second (\(v_0 = 26 \frac{m}{s}\)).
   
2. **Launch Angle (\(\theta_0\))**: The object is projected at an angle of 50 degrees to the horizontal (\(\theta_0 = 50°\)).
   
3. **Vertical Positions**:
   - The launch point is 3.5 meters above the ground.
   - The point where the object is supposed to be caught by the net is also positioned 3.5 meters above the ground.

4. **Horizontal Distances**:
   - The total horizontal distance from the launch point to the net is 26 meters.
   - The horizontal range (\(R\)) is the variable to be determined, representing the full horizontal distance covered by the projectile.

5. **Towers**:
   - There are three towers positioned between the launch point and the net.
   - Each tower has a height of 18 meters. 

### Diagram Elements:
- The object follows a parabolic trajectory from the launch point to the net, as indicated by the curved path.
- The diagram clearly shows the initial launch parameters and positions of obstacles (towers) and the final target (net).

### Explanation for Educational Website:
This diagram is an excellent representation of the principles of projectile motion, demonstrating how an object projected at an angle follows a parabolic path under the influence of gravity. Below are the steps to analyze the problem using the given information:

1. **Resolve Initial Velocity**: Break down the initial velocity (\(v_0\)) into its horizontal and vertical components.
   - \(v_{0x} = v_0 \cos(\theta_0)\)
   - \(v_{0y} = v_0 \sin(\theta_0)\)

2. **Determine Time of Flight**:
   - Use kinematic equations to calculate the time of flight, considering the object's rise and subsequent fall to the same vertical level (3.5 meters).

3. **Calculate Horizontal Range**:
   - Multiply the time of flight by the horizontal component of the velocity to find the horizontal distance covered.

4. **Analyze
Transcribed Image Text:### Projectile Motion Illustration The provided diagram depicts a classic example of projectile motion, taking place in a setting involving three towers and a net. Key elements and annotations are as follows: 1. **Initial Velocity (\(v_0\))**: The object is launched with an initial velocity of 26 meters per second (\(v_0 = 26 \frac{m}{s}\)). 2. **Launch Angle (\(\theta_0\))**: The object is projected at an angle of 50 degrees to the horizontal (\(\theta_0 = 50°\)). 3. **Vertical Positions**: - The launch point is 3.5 meters above the ground. - The point where the object is supposed to be caught by the net is also positioned 3.5 meters above the ground. 4. **Horizontal Distances**: - The total horizontal distance from the launch point to the net is 26 meters. - The horizontal range (\(R\)) is the variable to be determined, representing the full horizontal distance covered by the projectile. 5. **Towers**: - There are three towers positioned between the launch point and the net. - Each tower has a height of 18 meters. ### Diagram Elements: - The object follows a parabolic trajectory from the launch point to the net, as indicated by the curved path. - The diagram clearly shows the initial launch parameters and positions of obstacles (towers) and the final target (net). ### Explanation for Educational Website: This diagram is an excellent representation of the principles of projectile motion, demonstrating how an object projected at an angle follows a parabolic path under the influence of gravity. Below are the steps to analyze the problem using the given information: 1. **Resolve Initial Velocity**: Break down the initial velocity (\(v_0\)) into its horizontal and vertical components. - \(v_{0x} = v_0 \cos(\theta_0)\) - \(v_{0y} = v_0 \sin(\theta_0)\) 2. **Determine Time of Flight**: - Use kinematic equations to calculate the time of flight, considering the object's rise and subsequent fall to the same vertical level (3.5 meters). 3. **Calculate Horizontal Range**: - Multiply the time of flight by the horizontal component of the velocity to find the horizontal distance covered. 4. **Analyze
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