Improper Integral, Type II. 1 dx = In |x – 2| %3D X - 2 = In [4 – 2| – In 14 – 1| = In 2 – In 1 = In 2 %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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-find at least one error. 
-identify and explain the error in words. 
-finally correct the error(s). 

Improper Integral, Type II.
4
1
dx = In |x - 2|
4
%3D
X – 2
= In |4 – 2| – In |4 – 1|
= In 2 – In 1
= In 2
Transcribed Image Text:Improper Integral, Type II. 4 1 dx = In |x - 2| 4 %3D X – 2 = In |4 – 2| – In |4 – 1| = In 2 – In 1 = In 2
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