Immobilized glucose isomerase, sold commercially by Danish company Novozymes as Sweetzyme™, is used in an 8.0 L reactor to carry out the following reaction in the presence of an uncompetitive inhibitor, I: E + G <=1=> EG =2=> E + F EG + 1 <=3 => EIG The Sweetzyme beads have a total surface area of A = 750 cm². Kinetic Parameters k₁ = 0.0085 M¹¹ s¹ K-1 = 0.0017 s¹¹ k₂ = 0.72 s.¹ Initial/Total Enzyme concentration: Initial Bulk Substrate Concentration: Mass transfer coefficient, G = glucose, F = fructose E₁ = 3.2 x 10¹5 M Sb = 0.073 M k₁ = 8.5 x 104 cm/s A. What is the maximum reaction velocity with no inhibitor (in mol/L-s)? (recall that we solved for Vmax in terms of the kinetic rate constants for the uninhibited mechanism in class notes) B. What is the maximum reaction velocity (in mol/L-s) with the uncompetitive inhibitor, I, at a concentration of [1] = 0.0037 M, with K₁ = 2.1 x 10³ M. C. Calculate the Dahmköhler number to determine if the reaction is diffusion-limited or reaction-limited (i) when there is no inhibitor compared to Vmax (ii) when the uncompetitive inhibitor is present at [1] = 0.0037 M? Note: Use k₂ a, where a = surface area over reactor volume, when determining the Damkohler number.
Immobilized glucose isomerase, sold commercially by Danish company Novozymes as Sweetzyme™, is used in an 8.0 L reactor to carry out the following reaction in the presence of an uncompetitive inhibitor, I: E + G <=1=> EG =2=> E + F EG + 1 <=3 => EIG The Sweetzyme beads have a total surface area of A = 750 cm². Kinetic Parameters k₁ = 0.0085 M¹¹ s¹ K-1 = 0.0017 s¹¹ k₂ = 0.72 s.¹ Initial/Total Enzyme concentration: Initial Bulk Substrate Concentration: Mass transfer coefficient, G = glucose, F = fructose E₁ = 3.2 x 10¹5 M Sb = 0.073 M k₁ = 8.5 x 104 cm/s A. What is the maximum reaction velocity with no inhibitor (in mol/L-s)? (recall that we solved for Vmax in terms of the kinetic rate constants for the uninhibited mechanism in class notes) B. What is the maximum reaction velocity (in mol/L-s) with the uncompetitive inhibitor, I, at a concentration of [1] = 0.0037 M, with K₁ = 2.1 x 10³ M. C. Calculate the Dahmköhler number to determine if the reaction is diffusion-limited or reaction-limited (i) when there is no inhibitor compared to Vmax (ii) when the uncompetitive inhibitor is present at [1] = 0.0037 M? Note: Use k₂ a, where a = surface area over reactor volume, when determining the Damkohler number.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![Immobilized glucose isomerase, sold commercially by Danish company Novozymes as Sweetzyme™, is used in an 8.0 L
reactor to carry out the following reaction in the presence of an uncompetitive inhibitor, I:
E + G <=1=> EG =2=> E + F
EG + <=3 => EIG
The Sweetzyme beads have a total surface area of A = 750 cm².
Kinetic Parameters
k₁ = 0.0085 M¹¹ s¹
K-1 = 0.0017 s¹¹
k₂ = 0.72 s.¹
Initial/Total Enzyme concentration:
Initial Bulk Substrate Concentration:
Mass transfer coefficient,
G = glucose, F = fructose
E₁ = 3.2 x 105 M
Sb = 0.073 M
k₁ = 8.5 x 104 cm/s
A. What is the maximum reaction velocity with no inhibitor (in mol/L-s)?
(recall that we solved for Vmax in terms of the kinetic rate constants for the uninhibited mechanism in class notes)
B. What is the maximum reaction velocity (in mol/L-s) with the uncompetitive inhibitor, I, at a concentration of
[1] = 0.0037 M, with K₁ = 2.1 x 10³ M.
C. Calculate the Dahmköhler number to determine if the reaction is diffusion-limited or reaction-limited
(i) when there is no inhibitor compared to Vmax
(ii) when the uncompetitive inhibitor is present at [1] = 0.0037 M?
Note: Use k₂ a, where a = surface area over reactor volume, when determining the Damkohler number.
D. Calculate KM using the Rapid Equilibrium approach (we've solved for this in the class notes) and determine the
actual reaction velocity for the bulk substrate concentration given, Sb = 0.073 M with [1] = 0.0037 M. Will
the inhibited reaction with immobilized enzyme be reaction or diffusion limited? Determine the
production rate of fructose.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6fb3429f-a406-4812-82fc-346d6a20f662%2F96ad307e-a7aa-4200-ac47-eb4454843144%2Fncn5jsm_processed.png&w=3840&q=75)
Transcribed Image Text:Immobilized glucose isomerase, sold commercially by Danish company Novozymes as Sweetzyme™, is used in an 8.0 L
reactor to carry out the following reaction in the presence of an uncompetitive inhibitor, I:
E + G <=1=> EG =2=> E + F
EG + <=3 => EIG
The Sweetzyme beads have a total surface area of A = 750 cm².
Kinetic Parameters
k₁ = 0.0085 M¹¹ s¹
K-1 = 0.0017 s¹¹
k₂ = 0.72 s.¹
Initial/Total Enzyme concentration:
Initial Bulk Substrate Concentration:
Mass transfer coefficient,
G = glucose, F = fructose
E₁ = 3.2 x 105 M
Sb = 0.073 M
k₁ = 8.5 x 104 cm/s
A. What is the maximum reaction velocity with no inhibitor (in mol/L-s)?
(recall that we solved for Vmax in terms of the kinetic rate constants for the uninhibited mechanism in class notes)
B. What is the maximum reaction velocity (in mol/L-s) with the uncompetitive inhibitor, I, at a concentration of
[1] = 0.0037 M, with K₁ = 2.1 x 10³ M.
C. Calculate the Dahmköhler number to determine if the reaction is diffusion-limited or reaction-limited
(i) when there is no inhibitor compared to Vmax
(ii) when the uncompetitive inhibitor is present at [1] = 0.0037 M?
Note: Use k₂ a, where a = surface area over reactor volume, when determining the Damkohler number.
D. Calculate KM using the Rapid Equilibrium approach (we've solved for this in the class notes) and determine the
actual reaction velocity for the bulk substrate concentration given, Sb = 0.073 M with [1] = 0.0037 M. Will
the inhibited reaction with immobilized enzyme be reaction or diffusion limited? Determine the
production rate of fructose.
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