ime Magazine plans to do a telephone poll of adult Americans to ask them “How much are you worried about the quality of education in our schools?” for an upcoming article. a) They would like to be 95% confident in the result of survey and have a margin of error within 3% of the true population proportion. Suppose they have no estimate for what the sample proportion will be. How many people should they survey? b) Say they actually end up polling 1000 adults and find that 65% responded "a lot" to their survey question. We are interested in the population proportion of adult Americans who are worried “a lot” about the quality of education in our schools. Construct a 90% confidence interval for the population proportion around the given sample proportion. Give the Margin of Error as well. If there was another survey and the margin of error needed to be the same as in part b, but now 1750 people were surveyed instead of 1000, what would the new level of confidence be? Assume the sample proportion stayed the same. No hand written solution and no image

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Time Magazine plans to do a telephone poll of adult Americans to ask them “How much are you worried about the quality of education in our schools?” for an upcoming article.

a) They would like to be 95% confident in the result of survey and have a margin of error within 3% of the true population proportion. Suppose they have no estimate for what the sample proportion will be. How many people should they survey?

b) Say they actually end up polling 1000 adults and find that 65% responded "a lot" to their survey question. We are interested in the population proportion of adult Americans who are worried “a lot” about the quality of education in our schools. Construct a 90% confidence interval for the population proportion around the given sample proportion. Give the Margin of Error as well.

If there was another survey and the margin of error needed to be the same as in part b, but now 1750 people were surveyed instead of 1000, what would the new level of confidence be? Assume the sample proportion stayed the same. No hand written solution and no image 

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