Imagine you have two chemicals floating around in a chamber that react in equal quantities to make a product. The law of mass action tells that in this case, the rate of reaction is directly proportional to the product of concentrations of reactants. This leads to the following formula to find the time, T, taken by the chemical reaction to create a quantity q of the product (in molecules) from quantities a, b of reactants: k dx T(a) = , (a – a)(b – x)' where k is a positive constant depending on the chemicals and physical conditions. Suppose 0 < a < b. (a) Find the time taken to make a quantity q = a/2 of the product, i.e. to consume half of the a reactant. (b) Does the improper integral T(a) converge or diverge? What does this mean physically?

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Chapter2: Second-order Linear Odes
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Use knowledge of improper integrals to solve.

1. Imagine you have two chemicals floating around in a chamber that react in equal quantities
to make a product. The law of mass action tells that in this case, the rate of reaction is
directly proportional to the product of concentrations of reactants. This leads to the
following formula to find the time, T, taken by the chemical reaction to create a quantity q
of the product (in molecules) from quantities a, b of reactants:
T(q) = |
k dx
L (a – x)(b – x)'
-
where k is a positive constant depending on the chemicals and physical conditions. Suppose
0 < a < b.
(a) Find the time taken to make a quantity q = a/2 of the product, i.e. to consume half of
the a reactant.
(b) Does the improper integral T(a) converge or diverge? What does this mean physically?
(c) Consider the formula for T(a/2) you found in 1.a. What happens to T(a/2) as
6 → at? Give an interpretation of the constant k based on your answer.
Transcribed Image Text:1. Imagine you have two chemicals floating around in a chamber that react in equal quantities to make a product. The law of mass action tells that in this case, the rate of reaction is directly proportional to the product of concentrations of reactants. This leads to the following formula to find the time, T, taken by the chemical reaction to create a quantity q of the product (in molecules) from quantities a, b of reactants: T(q) = | k dx L (a – x)(b – x)' - where k is a positive constant depending on the chemicals and physical conditions. Suppose 0 < a < b. (a) Find the time taken to make a quantity q = a/2 of the product, i.e. to consume half of the a reactant. (b) Does the improper integral T(a) converge or diverge? What does this mean physically? (c) Consider the formula for T(a/2) you found in 1.a. What happens to T(a/2) as 6 → at? Give an interpretation of the constant k based on your answer.
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