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- For this year’s most important new toy, Holiday’s marketing director is expecting demand to average 40 units per retail outlet. Prior to making the final production decision based on this estimate, Holiday decided to survey a sample of 25 retailers in order to develop more information about the demand for the new product. Each retailer was provided with information about the features of the new toy along with the cost and the suggested selling price. Then each retailer was asked to specify an anticipated order quantity. Alpha = .05. Note: Calculate for the Sample Standard Deviation.The largest cat in North America is the Jaguar, they can sometimes be seen in the mountains of southern Texas, Arizona and New Mexico, (and less recently southern California). The rate of observances by humans is about 3/20 years. Assume we don't get Trump's border wall which would isolate the US population from the rest, and presumably cut off their chance of breeding. Chances of seeing 5 or more separate Jaguars within 5 years is 0.0011. a. Your cameras also produce pictures of wolf sized canids, either wolves or coy-wolves in the same region (very different times). Each year your cameras catch about 40 of these animals and about 30 cougars and about 400 bear and 800 feral Hogs. Assume that these numbers are all population rates for poisson. Given your camera Network catches a non human large animal (and the above list is all of them): What is the probability it is a jaguar? What is the probability it is a feral hog? Out of 15 large non-human animals, what is the probability…A hairdresser wanted to see if her clients bought more products at the end of their appointment if they were given lots of compliments. She decided to test this theory using an experiment. She randomly assigned 24 clients to receive either zero compliments, 5 compliments, or 10 compliments during their appointment. She recorded how many products they purchased after their appointment as her DV. She firstly hypothesised that no-compliment clients (M = 0.38) would purchase fewer products than clients who received 5 compliments (M = 1.50). She secondly hypothesised that 5-compliment clients would purchase fewer products than 10-compliment clients (M = 3.63). Thus, she conducted two comparisons. The initial ANOVA was significant. Using an alpha of .05, results for the follow-up tests confirmed her first hypothesis, with an obtained t value of 2.60, but did not confirm her second hypothesis, with an obtained t value of 1.20. She later realised that she did not use a Bonferroni-corrected…
- At wind speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 1000 cm/sec deposit sand and wind speeds above 1000 cm/sec move sand to new locations. The cyclic nature of wind and moving sand determines the shape and location of large dunes. At a test site, the prevailing direction of the wind did not change noticeably. However, the velocity did change. Sixty-three wind speed readings gave an average velocity of x = 1075 cm/sec. Based on long-term experience, ? can be assumed to be 255 cm/sec.You are a researcher who wants to know what the mean (µ) level of anxiety would be for the whole population if they were all receiving a new anti-anxiety therapy. You can’t give the therapy to the whole population, so you give it to a sample, and you get M = 32.1 as the average anxiety level for the sample on the therapy. What is the reason that you can’t just simply assume that µ = 32.1? You didn’t use random assignment Sampling error Descriptive statistics Inferential statisticsAt wind speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 1000 cm/sec deposit sand and wind speeds above 1000 cm/sec move sand to new locations. The cyclic nature of wind and moving sand determines the shape and location of large dunes. At a test site, the prevailing direction of the wind did not change noticeably. However, the velocity did change. Sixty-five wind speed readings gave an average velocity of x = 1075 cm/sec. Based on long-term experience, ? can be assumed to be 255 cm/sec. (a) Find a 95% confidence interval for the population mean wind speed at this site. (Round your answers to the nearest whole number.) lower limit ______cm/sec upper limit _____cm/sec
- Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 139 to 194 cm and weights of 39 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x= 167.63 cm, y = 81.47 kg, r=0.106, P-value = 0.294, and y = - 108 + 1.04x. Find the best predicted value of y (weight) given an adult male who is 172 cm tall. Use a 0.05 significance level. The best predicted value of y for an adult male who is 172 cm tall is kg. (Round to two decimal places as needed.)Previous studies have shown that playing video games can increase visual perception abilities on tasks presented in the gaming zone of the screen (within 5 degrees of the center). A graduate student is interested in whether playing video games increases peripheral visual perception abilities or decreases attention to peripheral regions because of focus on the gaming zone. For her study, she selects a random sample of 64 adults. The subjects complete a difficult spatial perception task to determine baseline levels of their abilities. After playing an action video game (a first-person combat simulation) for 1 hour a day over 10 days, they complete the difficult perception task for a second time. Before playing the action video game, the mean score in their accuracy on the spatial task was 0.42. After playing the action video game, the mean score was -0.08. The mean of the differences between each person's pre- and postscores was 0.5, with a standard deviation of the differences equal to…Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 133 to 188 cm and weights of 40 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.54 cm, y = 81.35 kg, r=0.186, P-value = 0.064, and y = - 109 + 1.12x. Find the best predicted value of ŷ (weight) given an adult male who is 180 cm tall. Use a 0.10 significance level. The best predicted value of y for an adult male who is 180 cm tall is (Round to two decimal places as needed.) kg.
- Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 132 to 193 cm and weights of 39 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.59 cm, y = 81.52 kg, r= 0.416, P-value = 0.000, and y = - 102 + 1.13x. Find the best predicted value of y (weight) given an adult male who is 147 cm tall. Use a 0.05 significance level. The best predicted value of y for an adult male who is 147 cm tall is kg. (Round to two decimal places as needed.)Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 137 to 189 cm and weights of 37 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.50 cm, y =81.41 kg, r=0.232, P-value = 0.020, and y = - 109 + 1.17x. Find the best predicted value of y (weight) given an adult male who is 145 cm tall. Use a 0.01 significance level. The best predicted value of y for an adult male who is 145 cm tall is kg. (Round to two decimal places as needed.)Question 4 The Department of Energy wants to determine the percentage of mining firms that follow energy saving production processes. A random sample of 250 mining firms was selected and it was found that 95 out of 250 firms follow these practices. Estimate with 99% confidence, the percentage interval of mining firms that practice the energy saving production processes. Use a critical value of 2,58.