Imagine A and B as some monodentate ligands with a single negative charge. We put a very small amount of the coordination complex [M(A)] in a very concentrated solution of Bions. Which statement best discusses the reason for what happens next?

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Imagine A and B as some monodentate ligands with a single negative charge.
We put a very small amount of the coordination complex [M(A)6] in a very
concentrated solution of Bions.
Which statement best discusses the reason for what happens next?
Not enough information: We would need to know something about the relative
strength of M-A bonds and M-B bonds to know if anything happens next
The M-A bonds will continuously break and re-form, and if there is enough of ligand
B around, the complex will eventually replace the A ligands, one by one
The complex will be so overwhelmed with B- ions that the A-ligands dissolve and B
replaces them.
O Nothing will happen because ligands stay where we put them
Transcribed Image Text:Imagine A and B as some monodentate ligands with a single negative charge. We put a very small amount of the coordination complex [M(A)6] in a very concentrated solution of Bions. Which statement best discusses the reason for what happens next? Not enough information: We would need to know something about the relative strength of M-A bonds and M-B bonds to know if anything happens next The M-A bonds will continuously break and re-form, and if there is enough of ligand B around, the complex will eventually replace the A ligands, one by one The complex will be so overwhelmed with B- ions that the A-ligands dissolve and B replaces them. O Nothing will happen because ligands stay where we put them
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