I'm working through a 2D PDE and i've gotten stuck (if the rest of my work is correct). so I'm getting confused checking the boundry conditions. first, no where says that a has to be a finite number so I dont know if this checks out (this might be a question for my teacher so no worries if you cant answer that). second is u(x,y=0,t) I'm not getting zero, I'm not sure where I'm going wrong?
I'm working through a 2D PDE and i've gotten stuck (if the rest of my work is correct). so I'm getting confused checking the boundry conditions. first, no where says that a has to be a finite number so I dont know if this checks out (this might be a question for my teacher so no worries if you cant answer that). second is u(x,y=0,t) I'm not getting zero, I'm not sure where I'm going wrong?

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VERIFY: ulo, y, z)
u(a, y, t)
K(x₁0, t) = (
Sin (0) = 0
= Sın (ait) =0
FOR
) Sin (TX) COS (0) +0
1?
a WHOLE NUMBE"
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As per the question we are given a candidate solution u(x,y,t) which fails to satisfy the boundary conditions to the 2d wave equation as :
u(a,y,t) ≠ 0 , u(x,b,t) ≠ 0 , u(x,0,t) ≠ 0
And we have to find the correct solution which satisfies all the boundary conditions.
Step by step
Solved in 2 steps with 1 images
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This doesn't make sense, a and b are already defined in the problem as 1...
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