Im not sure how to plug in my calculated values to get the theoretical non-standard cell potential for each battery. can someine explain?

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Im not sure how to plug in my calculated values to get the theoretical non-standard cell potential for each battery. can someine explain?

Nonstandard Conditions
Nernst equation:
Eº: reaction potential
n: number of moles of electrons transferred
Q: reaction quotient
2 Ag* (aq)
Q=
[Prod]A
E = E°-(0.0592/n) log Q
[React]B
Zn (s)
[Zn²+]
[Ag+]²
=
2 Ag (s) + Zn²+ (aq)
(0.50)
(0.025)²
+1.562 V
E = 1.562-(0.0592/2) log 800
E = 1.562-0.096 = 1.476 V
Agus)
2 mol e
= 800
Transcribed Image Text:Nonstandard Conditions Nernst equation: Eº: reaction potential n: number of moles of electrons transferred Q: reaction quotient 2 Ag* (aq) Q= [Prod]A E = E°-(0.0592/n) log Q [React]B Zn (s) [Zn²+] [Ag+]² = 2 Ag (s) + Zn²+ (aq) (0.50) (0.025)² +1.562 V E = 1.562-(0.0592/2) log 800 E = 1.562-0.096 = 1.476 V Agus) 2 mol e = 800
Battery I
cell voltage measured
Metal Anode zinc
metal cathode: Copper (0.1M) Cu
Battery 2
cell voltage measured
metal anode
Zinc
metal cathode: copper (0.010μ) Cu
Battery 3
battery 2
cell voltage measured
0.905 V
metal anodezine (0.100 M)
metal cathode: copper (0.001) Cu
Battery 1
Standard cell potential:
E cell Ecell
+
Ecele = 0.942 +070,942
0.942 V
(0.1 m)
Ecel=
battery 3 0.905 v
Ecell
0.913 V
(0.001 μ)
=
cell = 0.913 V
0.913+0.0591 (-1.51)
= 0.824 V
0.0692 In-
= For battery 1:
[+]
[Cu²+]
n
0.001
0.905 + 0,2591 In (0,100,
2
E= E-0₁0592
A
1,04 V
la=
Transcribed Image Text:Battery I cell voltage measured Metal Anode zinc metal cathode: Copper (0.1M) Cu Battery 2 cell voltage measured metal anode Zinc metal cathode: copper (0.010μ) Cu Battery 3 battery 2 cell voltage measured 0.905 V metal anodezine (0.100 M) metal cathode: copper (0.001) Cu Battery 1 Standard cell potential: E cell Ecell + Ecele = 0.942 +070,942 0.942 V (0.1 m) Ecel= battery 3 0.905 v Ecell 0.913 V (0.001 μ) = cell = 0.913 V 0.913+0.0591 (-1.51) = 0.824 V 0.0692 In- = For battery 1: [+] [Cu²+] n 0.001 0.905 + 0,2591 In (0,100, 2 E= E-0₁0592 A 1,04 V la=
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