I'm looking for help in approaching my question 11. A one-tailed hypothesis test with the t statisticAntisocial personality disorder (ASPD) is characterized by deceitfulness, reckless disregard for the well-being of others, a diminished capacity forremorse, superficial charm, thrill seeking, and poor behavioral control. ASPD is not normally diagnosed in children or adolescents, but antisocialtendencies can sometimes be recognized in childhood or early adolescence. James Blair and his colleagues have studied the ability of children withantisocial tendencies to recognize facial expressions that depict sadness, happiness, anger, disgust, fear, and surprise. They have found that childrenwith antisocial tendencies have selective impairments, with significantly more difficulty recognizing fearful and sad expressions.Suppose you have a sample of 40 16-year-old children with antisocial tendencies and you are particularly interested in the emotion of disgust. Theaverage 16-year-old has a score on the emotion recognition scale of 11.80. (The higher the score on this scale, the more strongly an emotion has tobe displayed to be correctly identified. Therefore, higher scores indicate greater difficulty recognizing the emotion). Assume that scores on the emotionrecognition scale are normally distributed.You believe that children with antisocial tendencies will have a harder time recognizing the emotion of disgust (in other words, they will have higherscores on the emotion recognition test).What is your null hypothesis stated using symbols? H,: Pantisocial S Hgeneral population ▼What is your alternative hypothesis stated using symbols? H,: Mantisocial > Hgeneral populationThis is a one-tailed test. Given what you know, you will evaluate this hypothesis using a tUsing the Distributions tool, locate the critical region for a = 0.05.t Distributionstatistic. t DistributionDegrees of Freedom = 33OOO^^^-3.0-2.0-1.00.01.02.03.0xIn order to use the t distribution, you will first need to determine the degrees of freedom (df) for a = 0.05. The degrees of freedom (df) is 39 ▼The critical value of t is 1.685Your sample of 16-year-old children with antisocial tendencies has an average score of 12.55 with a standard deviation of 3.28.The t statistic does not lie in the critical region. Therefore, you cannot reject the null hypothesis.Calculate the t statistic. To do this, you will first have to calculate the estimated standard error. The estimated standard error is 0.52. The tstatistic is 1.45 ▼ (Hint: For the most precise results, retain four significant figures from your calculation of the standard error to calculate the tstatistic.)Based on the results of this test, there is not enough evidence to conclude that children with antisocial tendencies have greater difficultyrecognizing disgust than do children without antisocial tendencies.

To test:Null hypothesis H0: There is no difference in the average score of average children and…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of BYU-Idaho students was surveyed and asked if they were in favor of retaining the penny as a form of currency in the United States. Out of the 116 women surveyed, 80 said that they were in favor of retaining the penny as a form of currency. Of the 137 men surveyed, 91 said that they were in favor of retaining the penny. Difference = Women - Men The picture below is the question. Use the information above to help.
Oh no! Our expert couldn't answer your question. Don't worry! We won't leave you hanging. Plus, we're giving you back one question for the inconvenience. Here's what the expert had to say: Hi and thanks for your question! Unfortunately we cannot answer this particular question due to its complexity. We've credited a question back to your account. Apologies for the inconvenience. Ask Your Question Again 30 of 30 questions left until 11/15/20 Question Should We Convict? A woman who was shopping in Los Angeles had her purse stolen by a young, blonde female who was wearing a ponytail. The blonde female got into a yellow car that was driven by a white male who had a mustache and a beard. The police located the blonde female named Janet Collins who wore her hair in a ponytail and had a friend who was a white male who had a mustache and beard and also drove a yellow car. The police arrested the two subjects. Because there were no eyewitnesses and no real evidence, the prosecution…
A random sample of BYU-Idaho students was surveyed and asked if they were in favor of retaining the penny as a form of currency in the United States. Out of the 116 women surveyed, 80 said that they were in favor of retaining the penny as a form of currency. Of the 137 men surveyed, 91 said that they were in favor of retaining the penny. Difference = Women - Men The picture below is the question. Use the information above to help.
I need help solving this Please! Thank you!
In 2004 it surfaced in Reader's Digest presented as having happened to a teacher at an unnamed community college. Four students walked in halfway through American history test my father was giving at the local community college. "Sorry," they said, "we had a flat tire." An understanding man, Dad said that if they could answer just one question correctly, he would give them each an "A" for the exam. The students agreed. So my father handed each one a piece of paper, placed them in four separate comers and said, "Write down which tire was flat." Kurt Smith What is the probability that these four students would give identical answers if they hadn't had a flat tire? Why?
I don't believe this answer is correct. Wouldn't it be "not enough information given to determine"? $12 is not the answer to this question.
i understand that it is option b but you did not tell me what goes in that box, there is a number ( ,y) that is there and you did not specify , could you please do
That is the first answer I got and it was also marked as incorrect. I am not sure why. I also tried the rounded version and it didn't work.
Negate the statement: ”No college students like Nickelback”.

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