Im having a lot of difficulty solving the blank part in the image. I can't figure out how to solve for the Natural Log (ln) relative rate vs. 1/T. As well as solving for the activation energy Ea for the reaction. Any help is highly appreciated. B. Effect of Temperature on Reaction Rate: The Activation EnergyemsTo find the activation energy for the reaction it will be helpful to complete the following table.The dependence of the rate constant, k', for a reaction is given by Equation 4:insmhoqxnoitone oE, A roitosoimeriO to eete(4)boo eind)Since the reactions at the different temperatures all involve the same reactant concentrations, the rate con-stants, k', for two different mixtures will have the same ratio as the reaction rates themselves for the two mix-In k' =--+ constantRTtures. This means that in the calculation of E, we can use the observed relative rates instead of rate constants.Proceeding as before, calculate the relative rates of reaction in each of the mixtures and enter these values in(c). Take the lIn rate for each mixture and enter these values in (d). To set up the terms in 1/T, fill in (b), (e),and (f) in the table.Approximate Temperature in °C2040100.(a) Time t in seconds for color to appear190.0413.82381.9765.323.15.263(b) Temperature of the reaction mixture in °C43.23.Z11.62.618522.8206 8(c) Relative rate = 1000/tL-30671.6607(d) In of relative rate3.12800.9626.2675(e) Temperature T in K296.25316.35284.75276.35(f) 1/T, K--003375 .003161.0035|1. 00368To evaluate E, make a graph of In relative rate vs. 1/T, using Excel or the graph paper provided. (SeeAppendix V.)Find the slope of the line obtained by drawing the best straight line through the experimental points.Slope =The slope of the line equals -E/R, where R = (8.31 joules/mole K) if E¸ is to be in joules per mole. Findthe activation energy, E, for the reaction.%3Da?E =joules/moleaC. Effect of a Catalyst on Reaction RateOptionalCatalyzedReaction 1Reaction 1Time for color to appear (seconds)190.0sec1.5secWould you expect the activation energy, E, for the catalyzed reaction to be greater than, less than, orequal to the activation energy for the uncatalyzed reaction? Why?

The explanation is given below-

Im having a lot of difficulty solving the blank part in the image. I can't figure out how to solve for the Natural Log (ln) relative rate vs. 1/T. As well as solving for the activation energy Ea for the reaction. Any help is highly appreciated

Im having a lot of difficulty solving the blank part in the image. I can't figure out how to solve for the Natural Log (ln) relative rate vs. 1/T. As well as solving for the activation energy Ea for the reaction. Any help is highly appreciated

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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In aqueous solution buffered at a pH of 6.75 Penicillin G (molecular weight of 334.39 g/mole) undergoes hydrolysis via a pseudo first order reaction that has an activation energy of 77.3 kJ/mole and a pseudo first order rate constant of 1.58 x 10-7 s-1 at 30°C. If a vial of Penicillin G containing 5,000,000 units is stored under the conditions above, how many days will it take for 10% of the drug to hydrolyze?
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