I'm confused with the R code, I'm supposed to do a 90% confidence interval at t=0.01. [1] -2.008559> y1=c(596,422,524,454,538,552,478,564,556)> y2=c(498,460,468,458,530,482,528,598,456)> t.test(y1,y2,paired-DT)taesPaired t-testdata: y1 and y2t = 1.1585, dfalternative hypothesis: true difference in means is not equal to 095 percent confidence interval:-22.67122 68.449008, p-value0.2801%3D!3!sample estimates:mean of the differences22.88889 (Exercise 8.2.2) In an experiment to compare two diets for fattening beef steers, nine pairs ofanimals were chosen from the herd: members of each pair were matched as closely as possiblewith respect to hereditary factors. The members of each pair were randomly allocated, oneto each diet. The following table shows the weight gains (Ib) of the animals over a 140 daytest period on diet 1 (Y1) and on diet 2 (Y2).PairDiet 1Diet 25964982422460352446844544585385306.552482 *478528564598556456(A) Calculate the standard error of the mean difference.(B) Test for a difference between the diets using a paired t test at a = 0.01.(C) Construct a 90% confidence interval for the difference in mean. Interpret the confidenceinterval.

It is given that the table shows the weight gains of the animals over a 140 day test period on diet.

Answered: I'm confused with the R code, I'm…

Math

Statistics

I'm confused with the R code, I'm supposed to do a 90% confidence interval at t=0.01.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Average

In mathematics, everyone must have heard the term average in one place or other. Almost all types of calculation require taking out an average. In everyday life, the term is used for denoting a certain amount that can be said to be a typical quantity for multiple people or objects. In other words, if a group of people possesses a certain object, then the average gives us an idea regarding the quantity of the object possessed by each person. However, this is solely based on mathematical calculation. It is important to note that most people will not strictly have the average value in a group.

Question

I'm confused with the R code, I'm supposed to do a 90% confidence interval at t=0.01.

[1] -2.008559
> y1=c(596,422,524,454,538,552,478,564,556)
> y2=c(498,460,468,458,530,482,528,598,456)
> t.test(y1,y2,paired-DT)
ta
es
Paired t-test
data: y1 and y2
t = 1.1585, df
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-22.67122 68.44900
8, p-value
0.2801
%3D
!3!
sample estimates:
mean of the differences
22.88889

(Exercise 8.2.2) In an experiment to compare two diets for fattening beef steers, nine pairs of
animals were chosen from the herd: members of each pair were matched as closely as possible
with respect to hereditary factors. The members of each pair were randomly allocated, one
to each diet. The following table shows the weight gains (Ib) of the animals over a 140 day
test period on diet 1 (Y1) and on diet 2 (Y2).
Pair
Diet 1
Diet 2
596
498
2
422
460
3
524
468
4
454
458
538
530
6.
552
482 *
478
528
564
598
556
456
(A) Calculate the standard error of the mean difference.
(B) Test for a difference between the diets using a paired t test at a = 0.01.
(C) Construct a 90% confidence interval for the difference in mean. Interpret the confidence
interval.

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