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im ²/1 In (4+¹) is Af'(4) where f(x) = ln x (B) (4) where f(x) = (In x)/x (C) f'(0) where f(x) = ln x (D) f (In 4) where f(x) = ln (4+x)/4 (E) f' (In 4) where f(x) = ln x ~> In (4th

im ²/1 In (4+¹) is Af'(4) where f(x) = ln x (B) (4) where f(x) = (In x)/x (C) f'(0) where f(x) = ln x (D) f (In 4) where f(x) = ln (4+x)/4 (E) f' (In 4) where f(x) = ln x ~> In (4th

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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how would you solve this question? this is a non graded practice. i’m mainly not sure how the (ln(4+h) - ln(4))/h simplifies but am confused about the overall problem. thank you!
Mim - In h→0 h 4+h is Af'(4) where f(x) = ln x . (B) (4) where f(x) = (In x)/x (C) f'(0) where f(x) = ln x (D) f (In 4) where f(x) = ln (4+x)/4 (E) f' (In 4) where f(x) = ln x lim — In (4th) = In (4th) 4-0 h -> In (4th) + Incus In (n+h) lim f(x+h)-f(x) h h-0 f(x) =In(x) f'(4) = lim h-so In 4th h lim in (4th) In h 4->0
Transcribed Image Text:Mim - In h→0 h 4+h is Af'(4) where f(x) = ln x . (B) (4) where f(x) = (In x)/x (C) f'(0) where f(x) = ln x (D) f (In 4) where f(x) = ln (4+x)/4 (E) f' (In 4) where f(x) = ln x lim — In (4th) = In (4th) 4-0 h -> In (4th) + Incus In (n+h) lim f(x+h)-f(x) h h-0 f(x) =In(x) f'(4) = lim h-so In 4th h lim in (4th) In h 4->0
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limit as h rightwards arrow 0 of 1 over h ln open parentheses fraction numerator 4 plus h over denominator 4 end fraction close parentheses

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