Illustration 17.35. The frequency distribution of the number ofmen killed by the kicks of horse in a certain Prussian army corps intwenty years is given as below (Von Bortkiewiez data):Deaths(x)134FrequencyFit a Poisson distribution to the data10965221Solu

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Answered: Illustration 17.35. The frequency…

MATLAB: An Introduction with Applications

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ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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QUESTION 13 Eighty hamsters were trained to run a maze. The frequency distribution below presents the number of trials it took each hamster to successfully complete the maze. # of Trials 1 2 3 5 6 7 10 Frequency 5 5 11 13 12 19 Make a histogram for this frequency distribution by hand and attach your file as a pdf, jpg, or png.
#23). Need help solving problem.
Illustration 11.13. From the following frequéncy distribution cal- culate the first four moments, B1 and B2. Class 10-14 1 15-19 4 20-24 8. 25-29 19 30-34 35 35-39 20 40-44 45 –49 1 50-54 5
Answer this question.
#16-17 Choose the letter of the correct answer.
Example3. Calculate Pearson's coefficient of skewness for the following data: X: 2 3 4 6. 7 f:1 3 13 8. 3
#18-19 Choose the letter of the correct answer.
Question # 7 The frequency distribution presented describes the speed at which young people drove to get to take their classes to university. These young men were driving on a highway with a speed limit of 35 mi / h. Calculate the variance and standard deviation. Frequency. speed 42-45 25 46-49 16 50-53 8 54-57 4 58-61 2
A random sample of people were selected in order to compare the hight between vegetarians and non-vegetarians. The relative-frequency histograms below show the height distribution of the fifteen vegetarian persons in the group and and the remaining people who are not vegetarian. What can be correctly concluded from these graphs? Vegetarian Not a Vegetarian 0.4 0.4 0.3 0.3 02 0.2 0.1 0.1 0.0 0.0 140 150 160 170 180 190 200 140 150 160 170 180 190 200 Height (cm) Height (cm) Select one or more: O a. being vegetarian causes people to be shorter on average O b. more than 30% of vegetarians in this study are between 160cm and 165cm tall Oc. the range of vegetarians heights is larger than the range of non-vegetarians heights O d. more than 45% of non-vegetarians in this study are more than 170cm tall Relative Frequency of Height (cm) Relative Frequency of Height (cm)
question 4 The data below are the ages in a Biology class at a 2-year college. Construct a Relative Frequency Distribution from the data, use 5 classes. 18, 18, 19, 21, 23, 24, 24, 25, 26, 26 27, 27, 28, 30, 32, 34, 35, 35, 38, 41
For number 1-6: A cost-of-living index measures the relative cost of living over time or regions. The following data pairs represent the cost of living index for grocery items (A) and health care (B) of the grouped urban areas. Groceries 99 97 110 97.3 114 99 71 91 109 120 127 98 115 105.9 96 8=12.55 S=G.44 1. What is the mean cost of living index for health items? A. 99.82 B. 72.68 C. 106.21 D. 101.34 2. Is the mean cost of living index for grocery higher than the mean cost of living index for health? A. Yes. B. No C. Cannot be determined 3. What is the absolute computed t-value? 2.88 A. B. 1.16 C. 1.34 A. D. 1.89 4. Given the tabulated t-2.306 at 5% level of significance, is the difference significant? A. Yes B. No 5. What is the decision to the problem? A. Accept Ho B. Reject Ho 6. What is the conclusion to the problem? A. 106 96.8 98 There is no significant difference in the mean cost of living indices for grocery and health. B. There is a significant difference in the mean cost of…
Q. 32. Calculate Q, and Qs for the following frequency distribution; Class Interval Frequency c.f. 5--9 10-14 6. 11 15-19 15 26 I 20-24 10 36 25-29 41 II 30-34 4 45 35-39 47 40-44 49 N=49

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Illustration 17.35. The frequency distribution of the number of men killed by the kicks of horse in a certain Prussian army corps in twenty years is given as below (Von Bortkiewiez data): Deaths (x) (f) Fit a Poisson distribution to the data 1 2 3 4 Frequency 109 65 22 3