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Illustrate the network diagram provided below, with the use of circle and arrows.

Illustrate the network diagram provided below, with the use of circle and arrows.

Practical Management Science
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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Illustrate the network diagram provided below, with the use of circle and arrows.

The above network diagram has five paths. The paths and their durations are as follows: Start -> A -> B -> C-> End {duration: 31 days.} Start ->D -> E ->F -> End {duration: 18 days.} Start -> D-> B -> C -> End {duration: 26 days.} Start -> G ->H ->I -> End {duration: 13 days.} Start -> G -> E ->F -> End {duration: 16 days.} Since the duration of the first path is the longest, it is the critical path. The float on the critical path is zero. The float for the second path "Start ->D -> E->F -> End" = duration of the critical path - duration of the path "Start ->D -> E->F -> End" = 31 - 18 = 13 Hence, the float for the second path is 13 days. Using the same process, we can calculate the float for other paths as well. Float for the third path = 31 - 26 = 5 days. Float for the fourth path = 31 – 13 = 18 days. Float for the fifth path = 31 - 16 = 15 days.
Transcribed Image Text:The above network diagram has five paths. The paths and their durations are as follows: Start -> A -> B -> C-> End {duration: 31 days.} Start ->D -> E ->F -> End {duration: 18 days.} Start -> D-> B -> C -> End {duration: 26 days.} Start -> G ->H ->I -> End {duration: 13 days.} Start -> G -> E ->F -> End {duration: 16 days.} Since the duration of the first path is the longest, it is the critical path. The float on the critical path is zero. The float for the second path "Start ->D -> E->F -> End" = duration of the critical path - duration of the path "Start ->D -> E->F -> End" = 31 - 18 = 13 Hence, the float for the second path is 13 days. Using the same process, we can calculate the float for other paths as well. Float for the third path = 31 - 26 = 5 days. Float for the fourth path = 31 – 13 = 18 days. Float for the fifth path = 31 - 16 = 15 days.
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