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Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Dislike also for incorrect () #
![This code segment find the
value of the result of following
series for five terms. *
Y
X = Val (Text1.Text)
N=1: K=1: S=0: C=1
1-.
X2 3X6 5X10
22 62 10²
+
S=S+K*T
K=-K: C=C+1
O
*****.
2-
3-.....
GoTo 20
10 Text2.Text = Str(S)
O
1-20 T = (x^(2*N))/ ((2 *N)^2) 2-N
= N +23-1f C = 6 Then Go To 10
1-20 T = (2*N) * (X^(2*N)) / ((2 * N)
^2) 2-N = N + 23-lf C = 6 Then GoTo
10
1-20 T = (N) * (X^(2* N)) / ((2 * N) ^
2) 2-N = N + 33-lf C = 6 Then GoTo 10
1-20 T = (N) * (X^(2 *N)) / ((2 * N) ^
2) 2-N = N + 23-1f C = 5 Then GoTo 10
1-20 T = (N) *(X^(2*N)) / ((2 *N) ^
2) 2-N = N +23-lf C = 41
= 4 Then GoTo 10
1-20 T = (N) * (X^(2 * N)) / ((2 * N) ^
2) 2-N = N +23-lf C = 6 Then GoTo 20
1-20 T = (N) * (X^ (2 * N)) / ((2 * N) ^
2) 2-N = N +23-1f C = 67
= 6 Then GoTo 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fff8bc427-4dd5-458f-a0de-0d1350ec468a%2F67ca1e3e-1750-45fc-b5f6-969882f53dfc%2Fudn0oir_processed.jpeg&w=3840&q=75)
Transcribed Image Text:This code segment find the
value of the result of following
series for five terms. *
Y
X = Val (Text1.Text)
N=1: K=1: S=0: C=1
1-.
X2 3X6 5X10
22 62 10²
+
S=S+K*T
K=-K: C=C+1
O
*****.
2-
3-.....
GoTo 20
10 Text2.Text = Str(S)
O
1-20 T = (x^(2*N))/ ((2 *N)^2) 2-N
= N +23-1f C = 6 Then Go To 10
1-20 T = (2*N) * (X^(2*N)) / ((2 * N)
^2) 2-N = N + 23-lf C = 6 Then GoTo
10
1-20 T = (N) * (X^(2* N)) / ((2 * N) ^
2) 2-N = N + 33-lf C = 6 Then GoTo 10
1-20 T = (N) * (X^(2 *N)) / ((2 * N) ^
2) 2-N = N + 23-1f C = 5 Then GoTo 10
1-20 T = (N) *(X^(2*N)) / ((2 *N) ^
2) 2-N = N +23-lf C = 41
= 4 Then GoTo 10
1-20 T = (N) * (X^(2 * N)) / ((2 * N) ^
2) 2-N = N +23-lf C = 6 Then GoTo 20
1-20 T = (N) * (X^ (2 * N)) / ((2 * N) ^
2) 2-N = N +23-1f C = 67
= 6 Then GoTo 10
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