IJC/06/II/1 The angle between the unit vectors a and b is 0. By expanding the scalar product, show that (3a-b) (a+3b)= 8cos 0. Given that 0= 60°, show that the length of projection of (3a-b) onto (a+3b) is V13

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IJC/06/II/1
The angle between the unit vectors a and b is 0.
By expanding the scalar product, show that (3a-b) (a+ 3b) =8cos 0.
%3D
4
Given that 0= 60°, show that the length of projection of (3a-b) onto (a+3b) is
V13
%3D
Transcribed Image Text:IJC/06/II/1 The angle between the unit vectors a and b is 0. By expanding the scalar product, show that (3a-b) (a+ 3b) =8cos 0. %3D 4 Given that 0= 60°, show that the length of projection of (3a-b) onto (a+3b) is V13 %3D
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