/IIII/II/ Start /////////I/ #include void BSort(int A[n][n]) { int temp; for(int j=0 ; j A[i+1]) { const int n=10; int Fact (int); void BSort(int A[n][n]); int main() { int A[n][n]; for(int i=0;i>A[i][j]; temp=A[i]; A[i]=A[i+1]; A[i+1]=temp; } } BSort(A); cout<<"Factorial = "<

/IIII/II/ Start /////////I/ #include void BSort(int A[n][n]) { int temp; for(int j=0 ; j A[i+1]) { const int n=10; int Fact (int); void BSort(int A[n][n]); int main() { int A[n][n]; for(int i=0;i>A[i][j]; temp=A[i]; A[i]=A[i+1]; A[i+1]=temp; } } BSort(A); cout<<"Factorial = "<

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include<iostream>#include<string>#include <cstdlib>#include <ctime>#include<time.h>#include <iomanip>using namespace std; void merge(string a[], string b[], int left, int mid, int right) {int nL = mid - left + 1;int nR = right - mid;string leftA[nL], rightA[nR], leftB[nL], rightB[nR];for(int i = 0; i < nL; i++) {leftA[i] = a[nL+i];leftB[i] = b[nL+i];}for(int i = 0; i < nR; i++) {rightA[i] = a[mid+i+1];rightB[i] = b[mid+i+1];}int i = 0, j = 0, k = left;while(i < nL && j < nR) {if(leftA[i] <= rightA[j]) {a[k] = leftA[i];b[k] = leftB[i];i++;}else {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}}while(i < nL) {a[k] = leftA[i];b[k] = leftB[i];i++;k++;}while(j < nR) {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}} void mergeSort(string a[], string b[], int left, int right) {int mid;if(left < right) {mid = left + (right-1)/2;mergeSort(a,b,left,mid);mergeSort(a,b,mid+1,right);merge(a,b,left,mid,right);}} int menu() {int…
Java Programming language Please help me with this question
#include <stdio.h>#include <stdlib.h>#include <math.h>#include <string.h>#define MAX 10 void generate_matrix( int M[MAX][MAX], int rows, int cols); int main(){int matrix[MAX][MAX], temp[MAX][MAX], R, C, i , j; printf("Enter number of rows (0 to exit): ");scanf("%d", &R); if (R <= 0)return 0; printf("Enter number of columns: ");scanf("%d", &C); generate_matrix (matrix, R, C);for(j=0; j<C; j++){for(i=0; i<R; i++){printf("%d\t", matrix[i][j]);;}printf("\n");} void generate_matrix( int M[MAX][MAX],int rows, int cols){int j, i; for(j=0; j<cols; j++){for(i=0; i<rows; i++){M[j][i] = (rand() % 9);}}} The generated matrix function is supposed to generate numbers 0-9But when i test it with ROW=5, COL=7, or when ROW!=COL the generated numbers are not in between the range.CAN you fix this issue ?
Python def fancy_quadratic(a: float, b: float, c: float, x: float) -> float: """ fancy_quadratic(a, b, c, x) returns a * x^2 + b*x + c # TODO: replace this TODO with examples of fancy_quadratic() :param a: coefficient a :param b: coefficient b :param c: coefficient c :param x: operand float value :returns: result of the operation """ pass # TODO: replace 'pass' with the function implementation # TODO: replace this line with the function signature described by the purpose: """ negate_a_mul_b(a, b) returns value of the operation -a * b example: negate_a_mul_b(-2.0, 1.0) -> 2.0 example: negate_a_mul_b(-2.0, -2.0) -> -4.0 example: negate_a_mul_b(1.0, -2.0) -> 2.0 example: negate_a_mul_b(0.0, 0.0) -> 0.0 TODO: add param and return descriptions here """ pass # TODO: replace 'pass' with the function implementation
#include<bits/stdc++.h>using namespace std;bool isPalindrome(string &s){ int start=0; int end=s.length()-1; while(start<=end) { if(s[start]!=s[end]) { return false; } start++; end--; } return true;}int main(){ string s; cout<<"ENTER STRING:"; getline(cin,s); int n=s.length(); bool flag=true; for(int i=1;i<n;i++) { string lowerHalf=s.substr(0,i); string upperHalf=s.substr(i,n-i); if(isPalindrome(lowerHalf) && isPalindrome(upperHalf)) { flag=false; cout<<"String A is:"<<lowerHalf<<"\n"; cout<<"String B is:"<<upperHalf<<"\n"; break; } } if(flag) { cout<<"NO\n"; } return 0;} change to stdio.h string.h
int X[900]; int Y[600]; int sum, sum1, sum2, sum3; //parallelism : dividing outer loop in three parts //i = 1 to 300 for(i=1;i<=300;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 301 to 600 for(i=301;i<=600;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 601 to 900 for(i=601;i<=900;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } sum = sum1 + sum2 + sum3;} another way to solve the question that send in the pic
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#include <iostream> using namespace std; // define a function // pass a 2d array as a parameter void display(float numbers[][2]) { cout << "Displaying Values: " << endl; for (int i = 0; i < 3; ++i) { for (int j = 0; j < 2; ++j) { cout << "num[" << i << "][" << j << "]: " << numbers[i][j] << endl; } } } int main() { // initializing the 2 dimensional array. int actions[3][2] = { {30, 704}, {70.9, 51.7}, {35.7, 11.92} }; return 0; } Display and explain your answer.
Write a code using c programming
void writeEmpToFile(Employee *emp, FILE *f) { fwrite(&emp->salary, sizeof(emp->salary), 1, f); fwrite(&emp->yearBorn, sizeof(emp->yearBorn), 1, f); fwrite(emp->ssn, sizeof(char), SSN_SIZE, f); int len = strlen(emp->name) + 1; fwrite(&len, sizeof(int), 1, f); fwrite(emp->name, sizeof(char), len, f); } If you don't want to look at all the code then please help me get the other section done from this code that I will put right here directly in the post if you need context on what this code needs to work with you can click on the link below https://onlinegdb.com/nWSAIx8hCn
Kindly fix the code:
In C programming. How do I find the max and min values of the corressponding columns. #include <stdio.h>#include <math.h>#include <stdlib.h>#define NROWS 5#define NCOLS 5 int main(void){ int i,j, max, min, m, n; float M[NROWS][NCOLS], Mt[NROWS][NCOLS]; char key_hit; //Input the sizes printf("ROW size(1-5) : ");scanf("%d",&m); printf("Column size(1-5): ");scanf("%d",&n); //Size Check while(m>NROWS || n>NCOLS) { printf("Please re-enter the sizes. \n"); printf("Row size(1-5) : ");scanf("%d", &m); printf("Column size(1-5) : ");scanf("%d", &n); } //Input the Matrix Data for(i=0; i<m; i++) for(j=0; j<n; j++) { printf("M[%d][%d] = ", i,j); scanf("%f", &M[i][j]); } //Print the Matrix Data for(i=0; i<m; i++) { for(j=0; j<n; j++) { printf("%1.2f\t", M[i][j]); }…