III. The figure below shows synchronous TDM, the data rate for each input connection is 1 Mbps. If 1 bit at a time is multiplexed, Find (a) the input bit duration, (b) the output bit duration, (c) the output bit rate, and (d) the output frame rate. ... 1 1 1 1 1 Mbps 1 ... 0 Frames O 0 0 0 1 Mbps 0101 0001 1101 0001 0101 1 0 1 MUX 0 1 1 Mbps *** 0 0 1 0 0 1 Mbps

III. The figure below shows synchronous TDM, the data rate for each input connection is 1 Mbps. If 1 bit at a time is multiplexed, Find (a) the input bit duration, (b) the output bit duration, (c) the output bit rate, and (d) the output frame rate. ... 1 1 1 1 1 Mbps 1 ... 0 Frames O 0 0 0 1 Mbps 0101 0001 1101 0001 0101 1 0 1 MUX 0 1 1 Mbps *** 0 0 1 0 0 1 Mbps

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The Fig 4.1 shows a demultiplexer of a TDM. If the frame size is 16 bits long (no synchronous / frame bits), what is the bit stream in each output? The bits arrive at the demultiplexer as shown by the arrow. 000011101010101010000111011100000111100011 Fig: 4.1
The figure below illustrates an asynchronous transmission in the form of short blocks. Each data bit is of 9.06 ms duration, start bit duration is 0.04ms more than a data bit duration, and each stop bit duration is double the duration of a start bit . Determine the bit rate and baud rate of the transmission. Data Bits Stop Bits Start Bit 1 101 0 10 010 1 Line is quiet! Direction of Data Data: 0100 1010
4. Three input channels need to be multiplexed using TDM, Their bit rates are 120 kbps, 80 kbps, and 40 kbps, respectively, (a) What is the required output bit rate for the TDM? (b) How to set the relative size of each time slot in one frame? (e) What is the minimum frame size and the corresponding frame rate?
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QUESTION 16 Determine the overhead and throughput for the following system. The system uses frames that begin with one start bit and end with 1 stop bit. The frame also contains five 7-bit ASCII characters and each character has one parity bit following it. overhead = 35/40, throughput = 5/40 overhead = 5/40, throughput = 35/40 overhead = 0.8333, throughput = 0.1667 overhead = 0.1667, throughput = 0.8333 overhead = 94.6%, throughput = 5.4% overhead = 5.4%, throughput = 94.6%