(III) An electron (mass m = 9.11 × 10-31 kg) is acceler- ated in the uniform field É (E = 1.45 x 10ʻ N/C) between two thin parallel charged plates. The separation of the plates is E 1.60 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate, Fig. 16–61. (a) With what speed does it leave the hole? (b) Show that the gravitational force can be ignored. FIGURE 16–61 Problem 36. + + + + + +

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Chapter1: Units, Trigonometry. And Vectors
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(III) An electron (mass m = 9.11 × 10-31 kg) is acceler-
ated in the uniform field É
(E = 1.45 x 10ʻ N/C) between
two thin parallel charged plates.
The separation of the plates is
E
1.60 cm. The electron is accelerated
from rest near the negative plate
and passes through a tiny hole
in the positive plate, Fig. 16–61.
(a) With what speed does it leave
the hole? (b) Show that the
gravitational force can be ignored.
FIGURE 16–61
Problem 36.
+
+
+
+
+
+
Transcribed Image Text:(III) An electron (mass m = 9.11 × 10-31 kg) is acceler- ated in the uniform field É (E = 1.45 x 10ʻ N/C) between two thin parallel charged plates. The separation of the plates is E 1.60 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate, Fig. 16–61. (a) With what speed does it leave the hole? (b) Show that the gravitational force can be ignored. FIGURE 16–61 Problem 36. + + + + + +
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