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ii. How many grams of solid tin will be formed? Calculate the approximate* pH of the final solution assuming it started as neutral and that the system could react to completion. ii.

ii. How many grams of solid tin will be formed? Calculate the approximate* pH of the final solution assuming it started as neutral and that the system could react to completion. ii.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you please help? I need help with C part 2 and 3.
NAME PER 7. Manganese(II) ions and tin (II) ions can react under the right conditions. Given are the oxidation and reduction half-reactions for such a system. Okidamon Mn²* + 4H,O → 8H* + MnO,¯ + 5e reduchon Sn²+ + 2e¯ → Sn (s) OVERALL: 24n2*+5 Sn2++8H20→55N(s) +164++ 2MN0 a. Label each of the half-reactions as either oxidation or reduction. b. Write the overall reaction and state how many electrons were transferred. c. Suppose 5.00 grams of Mn(NO,), was dissolved in 2500. mL of water and reacted completely with excess Sn2+ i. Why isn't nitrate included in the half reactions above? Nitreate isn't included in the half reaction because ii How many grams of solid tin will be formed? Calculate the approximate* pH of the final solution assuming it started as neutral and that the system could react to completion. iii. *This means we are assuming there is no formation of complex ions with water (because they are not included on the AP exam!! These would actually affect the pH a bit too, but not in a serious way). Also, HMNO, is actually a “secret" strong acid that no one cares about. Think about what that means for the effect that the MnO; ion has on pH. 9
Transcribed Image Text:NAME PER 7. Manganese(II) ions and tin (II) ions can react under the right conditions. Given are the oxidation and reduction half-reactions for such a system. Okidamon Mn²* + 4H,O → 8H* + MnO,¯ + 5e reduchon Sn²+ + 2e¯ → Sn (s) OVERALL: 24n2*+5 Sn2++8H20→55N(s) +164++ 2MN0 a. Label each of the half-reactions as either oxidation or reduction. b. Write the overall reaction and state how many electrons were transferred. c. Suppose 5.00 grams of Mn(NO,), was dissolved in 2500. mL of water and reacted completely with excess Sn2+ i. Why isn't nitrate included in the half reactions above? Nitreate isn't included in the half reaction because ii How many grams of solid tin will be formed? Calculate the approximate* pH of the final solution assuming it started as neutral and that the system could react to completion. iii. *This means we are assuming there is no formation of complex ions with water (because they are not included on the AP exam!! These would actually affect the pH a bit too, but not in a serious way). Also, HMNO, is actually a “secret" strong acid that no one cares about. Think about what that means for the effect that the MnO; ion has on pH. 9
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