II. Freezing point of a pure solid. Data Table. 1. mass of pure naphthaleneo nili13119 9.574g. anoli * 2. Freezing (melting ) point of naphthalene0.eCa 18.4°% III. Molecular weight by freezing point depression. SISU Data Table 1. mass of unknown * 2. Freezing (melting ) point of solution 72.3°0 Calculation (Carry out to proper number of significant digits.) 1. AT (difference in freezing points of pure naphthalene and solution) AT= oN awominU 2. molecular weight of unknown solute AT=Kfom KP Nmph= 7.0°G/ molal

II. Freezing point of a pure solid. Data Table. 1. mass of pure naphthaleneo nili13119 9.574g. anoli * 2. Freezing (melting ) point of naphthalene0.eCa 18.4°% III. Molecular weight by freezing point depression. SISU Data Table 1. mass of unknown * 2. Freezing (melting ) point of solution 72.3°0 Calculation (Carry out to proper number of significant digits.) 1. AT (difference in freezing points of pure naphthalene and solution) AT= oN awominU 2. molecular weight of unknown solute AT=Kfom KP Nmph= 7.0°G/ molal

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Freezing point
Name Time M T W R F The freezing point of pure benzene (CH,) is 5.50°C. The freezing point of a solution containing 5.00 g of an unknown non-dissociating solute in 444 g of benzene is 5.07°C. K, of benzene = 4.90°C/m. Show complete calculations for each question below. 1. What is the freezing point depression for this solution?
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D. Freezing Point Calculation Directions: Study the sample problem and do the task given. Sample problem with solution, Task to do Ethylene glycol (C2H6O2) is a molecular compound Calculate the freezing point of a solution that is used in many commercial anti-freezes. An aqueous solution of ethylene glycol is used in. vehicle radiators to prevent the water in the radiator from freezing by lowering its freezing point. Calculate the freezing point of a solution of 400. g of ethylene glycol in 500.g of water. repared by dissolving 27.56 g of glucose (C6H1206) into 125 g of water. Step 1: List the known quantities and plan the problem. Step 1: Kf (H2O) = -1.86 °C/m %3D Known: mass of C2H6O2 = 400. g molar mass of C2H6O2 = 62.08 g/mol mass of H20 = 500. g = 0.500 kg Kf (H20) = -1.86 °C/m *Kf- is the constant freezing point %3D %3D %3D %3DD ni noiulge Unknown: Tf of solution = ? °C *Tf- is the total freezing point This is a three-step problem. First, calculate the moles of ethylene glycol.…
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