(ii) Use the Fixed-Point Iteration method to find an approximation pN of the fixed-point p of g(x) in [1, 2], the root of the polynomial f(x) in [1, 2], satisfying RE(pN = PN-1) < 10-6 by taking po = 1 as the initial approximation. All calculations are to be carried out in the FPA7. Present the results of your calculations in a standard output table for the method of the form RE(pn ~ Pn-1) n Pn-1 Pn

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Chapter2: Second-order Linear Odes
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Numerical Analysis & it’s applications Q4 only part (ii) of the question needs answering. Part (i) is answered and the answer is included here. Thanks.
4. (Fired-Point Iteration Method;
Consider the problem of finding the root of the polynomial
f (x) = x* - 0.89x - 1.08
in [1, 2].
(i) Show that
f (x)
f'(x)
f(x) = 0 = x = x -
on [1, 2], thereby reducing the root-finding problem to the fixed-point problem for the function
f(x)
f'(x)
g(x) = x -
on [1,2].
(ii) Use the Fixed-Point Iteration method to find an approximation pN of the fixed-point p of g(x) in [1, 2], the root of the polynomial f(x) in
[1, 2], satisfying RE(pN PN-1) < 10-6 by taking po = 1 as the initial approximation. All calculations are to be carried out in the FPA7. Present
the results of your calculations in a standard output table for the method of the form
Pn-1
Pn RE(pn = Pn-1)
Transcribed Image Text:4. (Fired-Point Iteration Method; Consider the problem of finding the root of the polynomial f (x) = x* - 0.89x - 1.08 in [1, 2]. (i) Show that f (x) f'(x) f(x) = 0 = x = x - on [1, 2], thereby reducing the root-finding problem to the fixed-point problem for the function f(x) f'(x) g(x) = x - on [1,2]. (ii) Use the Fixed-Point Iteration method to find an approximation pN of the fixed-point p of g(x) in [1, 2], the root of the polynomial f(x) in [1, 2], satisfying RE(pN PN-1) < 10-6 by taking po = 1 as the initial approximation. All calculations are to be carried out in the FPA7. Present the results of your calculations in a standard output table for the method of the form Pn-1 Pn RE(pn = Pn-1)
Step1
a)
let un eapress
Step3
c)
fen=o s a
x approximale fro by
eguahin win Ihe neghbourhood of
forat degre e equahan.
(0.89*1.06)"s
中ca)
prh degure
Ihe
Iheri
may
wrile
frm= aox+ a, = 6-0
Step2
Ashere a.t0. and a, ave arbihom
pavamelas. a be
appropnale Cnditans
delnmınid by preseribed
on f ) and ils denvaluis
b)
tiwo
ocx ) = (os9x + os )
on Substiluting ao and a, from O sin and represtenting
hi approximalue volues a x by xes ocue
obtain
%3D
Frax)
he problem of tinding rat of he eg Ois egenvaled
at lhe point (**itx) wilk Ihi
The
evaluahen'. fe, te' each eleration
(o-59)
let
X0=1+2=1-5
Lwi
d'ns) =
Repsomilhd reuirg
Newton
Suppore x* s the exact
8olution for= 0
At he 4 N-R. ite vaten,
defne lhe erm (Ei:
whuch es dhaving cğuadrahc
Convergina - EurCCEE, cs Canaloint
fro is molle and f'ram)fo
and 1x-x* |l fmook endugh
Ysdoal Comurrgence
%3D
0-2391
く1
%3D
=1-2466
, (a ): Co$9+ 1-08)""= (6 89 C1·2u6o)t 18)"-2164
$3c*)= (o89*2+ •08) "4 = Co•84 (1.21b4) +1•08)"4=t2167
fuca)= (o$9x3+1.08)4 = (089 (1:2167) +1 es) "4 = 1-2
f5107= Cofs ry t1-08)"4= (05s c1iz123)+18); 1-2122
The rool by ed point levaħau
Critenm
4 212と
=) 1= $(2)
1/4
x =1.21 22 E(!,2]
Transcribed Image Text:Step1 a) let un eapress Step3 c) fen=o s a x approximale fro by eguahin win Ihe neghbourhood of forat degre e equahan. (0.89*1.06)"s 中ca) prh degure Ihe Iheri may wrile frm= aox+ a, = 6-0 Step2 Ashere a.t0. and a, ave arbihom pavamelas. a be appropnale Cnditans delnmınid by preseribed on f ) and ils denvaluis b) tiwo ocx ) = (os9x + os ) on Substiluting ao and a, from O sin and represtenting hi approximalue volues a x by xes ocue obtain %3D Frax) he problem of tinding rat of he eg Ois egenvaled at lhe point (**itx) wilk Ihi The evaluahen'. fe, te' each eleration (o-59) let X0=1+2=1-5 Lwi d'ns) = Repsomilhd reuirg Newton Suppore x* s the exact 8olution for= 0 At he 4 N-R. ite vaten, defne lhe erm (Ei: whuch es dhaving cğuadrahc Convergina - EurCCEE, cs Canaloint fro is molle and f'ram)fo and 1x-x* |l fmook endugh Ysdoal Comurrgence %3D 0-2391 く1 %3D =1-2466 , (a ): Co$9+ 1-08)""= (6 89 C1·2u6o)t 18)"-2164 $3c*)= (o89*2+ •08) "4 = Co•84 (1.21b4) +1•08)"4=t2167 fuca)= (o$9x3+1.08)4 = (089 (1:2167) +1 es) "4 = 1-2 f5107= Cofs ry t1-08)"4= (05s c1iz123)+18); 1-2122 The rool by ed point levaħau Critenm 4 212と =) 1= $(2) 1/4 x =1.21 22 E(!,2]
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