(ii) the magnitude of power dissipated through resistance Ri and (iil) the magnitude of power dissipated through resistance Ra.

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Chapter1: Units, Trigonometry. And Vectors
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### Problem Statement:

**Given:**  
- \( R_1 = 10 \, \Omega \) 
- \( R_2 = 15 \, \Omega \) 
- \( R_3 = 22 \, \Omega \) 
- \( R_4 = 10 \, \Omega \)

**Objective:**  
Find (i) the equivalent resistance of the circuit, (ii) the magnitude of power dissipated through resistance \( R_3 \), and (iii) the magnitude of power dissipated through resistance \( R_4 \).

### Diagram Explanation:

The circuit diagram consists of four resistors \( R_1, R_2, R_3, \) and \( R_4 \) connected to a 12V battery. 

- \( R_1 \) and \( R_2 \) are connected in parallel.
- \( R_3 \) is connected in series with the parallel combination of \( R_1 \) and \( R_2 \).
- \( R_4 \) is also connected in series with the remaining combination.

### Analyses Required:

1. **Equivalent Resistance Calculation:**
   - Calculate the equivalent resistance for \( R_1 \) and \( R_2 \) in parallel.
   - Add the equivalent resistance of \( R_1 \) and \( R_2 \) with \( R_3 \) and \( R_4 \) in series.

2. **Power Calculation:**
   - Use the formula \( P = I^2 R \) or \( P = \frac{V^2}{R} \) to calculate power dissipation across \( R_3 \) and \( R_4 \), where \( V \) is the voltage across the resistor and \( I \) is the current through the resistor.

This setup allows learners to practice using series and parallel circuit rules to solve for resistance and power in electrical circuits.
Transcribed Image Text:### Problem Statement: **Given:** - \( R_1 = 10 \, \Omega \) - \( R_2 = 15 \, \Omega \) - \( R_3 = 22 \, \Omega \) - \( R_4 = 10 \, \Omega \) **Objective:** Find (i) the equivalent resistance of the circuit, (ii) the magnitude of power dissipated through resistance \( R_3 \), and (iii) the magnitude of power dissipated through resistance \( R_4 \). ### Diagram Explanation: The circuit diagram consists of four resistors \( R_1, R_2, R_3, \) and \( R_4 \) connected to a 12V battery. - \( R_1 \) and \( R_2 \) are connected in parallel. - \( R_3 \) is connected in series with the parallel combination of \( R_1 \) and \( R_2 \). - \( R_4 \) is also connected in series with the remaining combination. ### Analyses Required: 1. **Equivalent Resistance Calculation:** - Calculate the equivalent resistance for \( R_1 \) and \( R_2 \) in parallel. - Add the equivalent resistance of \( R_1 \) and \( R_2 \) with \( R_3 \) and \( R_4 \) in series. 2. **Power Calculation:** - Use the formula \( P = I^2 R \) or \( P = \frac{V^2}{R} \) to calculate power dissipation across \( R_3 \) and \( R_4 \), where \( V \) is the voltage across the resistor and \( I \) is the current through the resistor. This setup allows learners to practice using series and parallel circuit rules to solve for resistance and power in electrical circuits.
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