(ii) say whether H(e) as a function of w is even or odd or neither (iii) and sketch/plot the magnitude of the frequency response, i.e., |H(e³w)|, over −2ñ < w ≤ 2π (you may use Matlab). (a) response of the system: In each figure, the value indicated for each impulse means the amplitude of that impulse. For example, if the value of an impulse at n = 3 is indicated to be 2j, it means 2jd[n − 3]. The value of h[n] is zero for all n outside the range shown in the figure. h[n] (b) (c) H(ejw) = Σ h[n]e¯¡nw, n=-x h[n] il -6-5-4-3-2-1 0 1 2 3 4 5 6 1 1 1 h[n] -6-5-4-3-2-1 0 1 2 3 456 -6 -5 -4 -3 -2 -1 0 −1 1 1 1 1 1 2 3 4 5 6 n h[n] is real-valued. h[n] is real-valued. h[n] is real-valued.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Problem 2
Each of the following figures shows the impulse response of a LTI system h[n]. For each
figure in (a), (b), (c) and (d):
(i) Firstly write an expression of h[n] and then find an expression of the frequency
response of the system:
h[n]e-inw
(ii) say whether H(e) as a function of w is even or odd or neither
(iii) and sketch/plot the magnitude of the frequency response, i.e., H(ew)|, over -27 <
w 2π (you may use Matlab).
(a)
(b)
In each figure, the value indicated for each impulse means the amplitude of that impulse.
For example, if the value of an impulse at n = 3 is indicated to be 2j, it means 2jd[n – 3].
The value of h[n] is zero for all n outside the range shown in the figure.
h[n]
(c)
H(ejw) =
h[n]
1 1 1
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
h[n]
-6 -5 -4 -3 -2 -1 0 1
-6-5-4-3-2-1 0
1
n=-∞
1
1
1 1 1
2
3 4
5
6
2 3 4 5 6
n
n
h[n] is real-valued.
h[n] is real-valued.
h[n] is real-valued.
Transcribed Image Text:Problem 2 Each of the following figures shows the impulse response of a LTI system h[n]. For each figure in (a), (b), (c) and (d): (i) Firstly write an expression of h[n] and then find an expression of the frequency response of the system: h[n]e-inw (ii) say whether H(e) as a function of w is even or odd or neither (iii) and sketch/plot the magnitude of the frequency response, i.e., H(ew)|, over -27 < w 2π (you may use Matlab). (a) (b) In each figure, the value indicated for each impulse means the amplitude of that impulse. For example, if the value of an impulse at n = 3 is indicated to be 2j, it means 2jd[n – 3]. The value of h[n] is zero for all n outside the range shown in the figure. h[n] (c) H(ejw) = h[n] 1 1 1 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 h[n] -6 -5 -4 -3 -2 -1 0 1 -6-5-4-3-2-1 0 1 n=-∞ 1 1 1 1 1 2 3 4 5 6 2 3 4 5 6 n n h[n] is real-valued. h[n] is real-valued. h[n] is real-valued.
Expert Solution
Step 1

Given:

Three different Impulse response sequences.

To find:

For each of impulse response, we have to find out the 

i) Expression of h[n] and frequency response of h[n].

ii) Say whether H(ejω) as a function of w is even or odd or neither.

iii) Magnitude plot of frequency response over -2π to 2π

 

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