II Let S be a circle with its center at point O and a radius of 1. Let AABC be a triangle such that all its vertices are on S and AB : AC = 3:2. As shown in the figure, let D be a point on the extension of side BC and k be the number BC: CD = 2: k. B Moreover, set OA = a, OB = 5, od - 7. Answer the following questions. (1) When we express OD in terms of 6, c and k, we have OD B C (2) Since the equality holds, by expressing the inner product a-6 in terms of the inner product ae, we have a (3) It follows that when the tangent to S at the point A passes through the point D, K

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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E (ơ
Vo)) 4G
LTE1
27% 0 11:08 PM
You
Just now
II
Let S be a circle with its center at point O and a
radius of 1. Let AABC be a triangle such that all
its vertices are on S and AB: AC = 3:2. As shown
in the figure, let D be a point on the extension of
side BC and k be the number where
BC: CD = 2: k.
Moreover, set
OA = a, OB = 5, oc =.
Answer the following questions.
(1)
When we express OD in terms of 6, e and k, we have
OD =
в
C
(2)
Since the equality
= |
holds, by expressing the inner product a - b in terms of the inner product a e, we have
H
G
(3)
It follows that when the tangent to S at the point
passes through the point D,
k =
K
Transcribed Image Text:E (ơ Vo)) 4G LTE1 27% 0 11:08 PM You Just now II Let S be a circle with its center at point O and a radius of 1. Let AABC be a triangle such that all its vertices are on S and AB: AC = 3:2. As shown in the figure, let D be a point on the extension of side BC and k be the number where BC: CD = 2: k. Moreover, set OA = a, OB = 5, oc =. Answer the following questions. (1) When we express OD in terms of 6, e and k, we have OD = в C (2) Since the equality = | holds, by expressing the inner product a - b in terms of the inner product a e, we have H G (3) It follows that when the tangent to S at the point passes through the point D, k = K
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