II f(x, y, z) dV for the specified function 3. f(x, y, z) = xe"-22; 0< x < 2, 0< y< 1, 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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II f(x, y, z) dV for the specified function
3. f(x, y, z) = xe"-22; 0< x < 2, 0< y< 1, 0<z<1
In Exercises 1-8, evaluate
f and box B.
1. f(x, y, z) = xz + yz²; 0< x < 2, 2< y < 4, 0<2< 4
2. f(x, y, z) = xy+ z²; [-2, 2] × [0, 1] × [0, 2]
(y + 2)² ; [0, 2] × [2, 4]) × [–1,1]
5. f(x, y, z) = (x – y)(y – 2); [0, 1] × [0, 3] × [0, 3]
4. f(x, y, z) =
6. f(x, y, z) = -; 1<x<3, 0< y< 2, 0<z< 4
7. f(x, y, z) = (x + 2)³; [0, a] × [0, b] × [0, c]
8. f(x, y, z) = (x + y – z)*; [0, a] × [0, b] × [0, c]
Transcribed Image Text:II f(x, y, z) dV for the specified function 3. f(x, y, z) = xe"-22; 0< x < 2, 0< y< 1, 0<z<1 In Exercises 1-8, evaluate f and box B. 1. f(x, y, z) = xz + yz²; 0< x < 2, 2< y < 4, 0<2< 4 2. f(x, y, z) = xy+ z²; [-2, 2] × [0, 1] × [0, 2] (y + 2)² ; [0, 2] × [2, 4]) × [–1,1] 5. f(x, y, z) = (x – y)(y – 2); [0, 1] × [0, 3] × [0, 3] 4. f(x, y, z) = 6. f(x, y, z) = -; 1<x<3, 0< y< 2, 0<z< 4 7. f(x, y, z) = (x + 2)³; [0, a] × [0, b] × [0, c] 8. f(x, y, z) = (x + y – z)*; [0, a] × [0, b] × [0, c]
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