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Firstly it is required to determine the MLE of the parameter and then the variance to get the required confidence interval.
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- 7. What is the 95% confidence interval for the difference in the population means, µ1 - µ2, given the data from the two independent samples: n1 =56, x1= 58.2, s1= 4.3, n2=45, x2=60.2, s2=5.5 B. [-3.28 , -0.72] C. [-3.60, -0.40] D. [-3.65 , -0.35] A. [-3.96 , -0.04] 8. What is the 98% confidence interval for the difference in the population means, µ1 - µ2, given: n1= 22, x1= 41.4, s1= 5.9, n2= 19, x2= 43.2, s2= 6.5 D. [-3.48 , -0.12] B. [-3.07 , -0.53] A. [-3.12, -0.48] C. [-3.18, -0.42]A previous study estimated the value of p to be 0.54. Find the minimum sample size required to ensure that your estimate ("p) will be within 0.01 of p with 90% confidence.Please let me know if I calculated relative risk correctly. Thank you for your assistance.
- How large should a sample be to estimate the population mean within [68.71, 71.29] with a 99% confidence interval if the sample mean is 70 and the population variance was 9 Select one: a. n= 26 b. n= 46 C. n= 16 O d. n= 36You are going to create a 99% confidence interval for the mean amount ofsugar in coffee shop specialty drinks. You know the population standarddeviation is σ = 5.9 grams. You want your confidence interval to have amargin of error of 0.25 grams. How big should your sample size be to obtainthis margin of error?1. Suppose that the weight of 100 male students of a university represent a random sample of weight of 1546 students of the university. Find 99% confidence interval for the mean weight of the students, given X = 67.45 and s 2. 93. =
- IID Suppose X1, ..., X, N(u, o?). Construct a 95% confidence interval for o? when u is known.2. Scored obtained by a large group of students taking a test are known to be normally distributed. A random sample of twenty-five students test scores yielded the following statistics: 25 と=1Xi 25 1508 x - 95628 Find a 95% confidence interval for the population mean.The z confidence interval for the mean of a Normal population will have a specified margin of error m when the sample size is: a. n = (=*o/m). b. n = (z/m)². O c. n = (*o/m)². d. n ==*o/m.