Please solve part 2 Leucine (see structure below); is a branched-chain aliphatic amino acid that is closely related toL-Valine. Its an essential amino acid and is utilized in the liver, adipose tissue and muscle tissue.CH3CH3OHH,NpKaj = 2.36pK2 = 9.60L-Leucine (H,L*)(i)What is the pH when the overall net charge on L-Leucine is equal to zero?pka,t pkaz2.36 + 9.60%3D11.96PH=- 5.9822PH= 5.98(ii)equilibrium pH for a solution that contains 15.00 mL of 0.2000M of H,L* form of L-Leucine(i.e. the fully protonated form) and 55.00 mL of 0.10000M NaOH.Using the chemical notations we used in lecture for amino acid, calculate the

Given that, Average pka of leucine = 5.98 Molarity of NaOH solution = 0.1 M Volume of NaOH…

(ii) equilibrium pH for a solution that contains 15.00 mL of 0.2000M of H,L* form of L-Leucine (i.e. the fully protonated form) and 55.00 mL of 0.10000M NaOH. Using the chemical notations we used in lecture for amino acid, calculate the

(ii) equilibrium pH for a solution that contains 15.00 mL of 0.2000M of H,L* form of L-Leucine (i.e. the fully protonated form) and 55.00 mL of 0.10000M NaOH. Using the chemical notations we used in lecture for amino acid, calculate the

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Please solve part 2

Leucine (see structure below); is a branched-chain aliphatic amino acid that is closely related to
L-Valine. Its an essential amino acid and is utilized in the liver, adipose tissue and muscle tissue.
CH3
CH3
OH
H,N
pKaj = 2.36
pK2 = 9.60
L-Leucine (H,L*)
(i)
What is the pH when the overall net charge on L-Leucine is equal to zero?
pka,t pkaz
2.36 + 9.60
%3D
11.96
PH=
- 5.98
2
2
PH= 5.98
(ii)
equilibrium pH for a solution that contains 15.00 mL of 0.2000M of H,L* form of L-Leucine
(i.e. the fully protonated form) and 55.00 mL of 0.10000M NaOH.
Using the chemical notations we used in lecture for amino acid, calculate the

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