(ii) Calculate the junction temperature of the IRF520 Mosfet using the parameters in the table below. The Mosfet is conducting a dc current of 6.5A and is mounted on a heatsink which is cooled by a fan. The air speed out of the fan is 1.5m/s. The maximum ambient temperature is 45°C. Mosfet Rth junction to case= 2.5 K/W Mosfet Rth junction to ambient = 62 K/W Mosfet Ros(on) = 0.270 Heatsink Rth natural convection = 5 K/W Mosfet Rth case to surface = 0.5K/W a 0,8 0,6 0,4 0,2 1 Heatsink forced convection multiplier (a) given in graph above 2 3 4 5 6 v [m

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(ii) Calculate the junction temperature of the IRF520 Mosfet using the parameters in the table
below. The Mosfet is conducting a dc current of 6.5A and is mounted on a heatsink which is
cooled by a fan. The air speed out of the fan is 1.5m/s. The maximum ambient temperature
is 45°C.
Mosfet Rth junction to case= 2.5 K/W
Mosfet Rth junction to ambient = 62 K/W
Mosfet Ros(on) = 0.270
Heatsink Rth natural convection = 5 K/W
Mosfet Rth case to surface = 0.5K/W
a
0,8
0,6
0,4
0,2
0
1
Heatsink forced convection multiplier (a) given in graph above
2
3
4
(iii) Explain how a dc\dc converter, rated at 100W @25°C, can be used at ambient
temperatures of 60°C?
5
6 V[m
Transcribed Image Text:(ii) Calculate the junction temperature of the IRF520 Mosfet using the parameters in the table below. The Mosfet is conducting a dc current of 6.5A and is mounted on a heatsink which is cooled by a fan. The air speed out of the fan is 1.5m/s. The maximum ambient temperature is 45°C. Mosfet Rth junction to case= 2.5 K/W Mosfet Rth junction to ambient = 62 K/W Mosfet Ros(on) = 0.270 Heatsink Rth natural convection = 5 K/W Mosfet Rth case to surface = 0.5K/W a 0,8 0,6 0,4 0,2 0 1 Heatsink forced convection multiplier (a) given in graph above 2 3 4 (iii) Explain how a dc\dc converter, rated at 100W @25°C, can be used at ambient temperatures of 60°C? 5 6 V[m
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