(ii) Calculate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD The half- reactions are: Acetaldehyde + 2H + 2e Ethanol NAD + 2H + 2e - NADH + H- E"= - 0.20V E"= - 0.32V (F= 96.485 kJ/V/mol)
(ii) Calculate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD The half- reactions are: Acetaldehyde + 2H + 2e Ethanol NAD + 2H + 2e - NADH + H- E"= - 0.20V E"= - 0.32V (F= 96.485 kJ/V/mol)
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
Question
answer ii only
![(i)
Calculate the physiological AG (not AG.') for the reaction:
Phosphocreatine + ADP creatine + ATP
Given;
Phosphocreatine + H20 → creatine + Pi
ADP + Pi → ATP + H:0
AG,' = -43 kJ/mol
AG.' =+30.5 kJ/mol
at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at
4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM.
(R= 8.315 JK' mol"')
(ii)
Calculate the free energy change at standard conditions for the following reaction:
Acetaldehyde + NADH + H* + Ethanol + NAD
The half- reactions are:
Acetaldehyde + 2H + 2e + Ethanol
NAD + 2H + 2e +
E"= - 0.20V
NADH + H-
E°"= - 0.32V
(F= 96.485 kJ/V/mol)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F875cac72-0f82-4647-92a7-f5dce3b969ce%2Fcc402c49-b983-4b10-a03f-2d55f0951d8f%2Fqhjeagg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(i)
Calculate the physiological AG (not AG.') for the reaction:
Phosphocreatine + ADP creatine + ATP
Given;
Phosphocreatine + H20 → creatine + Pi
ADP + Pi → ATP + H:0
AG,' = -43 kJ/mol
AG.' =+30.5 kJ/mol
at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at
4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM.
(R= 8.315 JK' mol"')
(ii)
Calculate the free energy change at standard conditions for the following reaction:
Acetaldehyde + NADH + H* + Ethanol + NAD
The half- reactions are:
Acetaldehyde + 2H + 2e + Ethanol
NAD + 2H + 2e +
E"= - 0.20V
NADH + H-
E°"= - 0.32V
(F= 96.485 kJ/V/mol)
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