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(ii) Calculate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD The half- reactions are: Acetaldehyde + 2H + 2e Ethanol NAD + 2H + 2e - NADH + H- E"= - 0.20V E"= - 0.32V (F= 96.485 kJ/V/mol)

(ii) Calculate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD The half- reactions are: Acetaldehyde + 2H + 2e Ethanol NAD + 2H + 2e - NADH + H- E"= - 0.20V E"= - 0.32V (F= 96.485 kJ/V/mol)

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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(i) Calculate the physiological AG (not AG.') for the reaction: Phosphocreatine + ADP creatine + ATP Given; Phosphocreatine + H20 → creatine + Pi ADP + Pi → ATP + H:0 AG,' = -43 kJ/mol AG.' =+30.5 kJ/mol at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM. (R= 8.315 JK' mol"') (ii) Calculate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD The half- reactions are: Acetaldehyde + 2H + 2e + Ethanol NAD + 2H + 2e + E"= - 0.20V NADH + H- E°"= - 0.32V (F= 96.485 kJ/V/mol)
Transcribed Image Text:(i) Calculate the physiological AG (not AG.') for the reaction: Phosphocreatine + ADP creatine + ATP Given; Phosphocreatine + H20 → creatine + Pi ADP + Pi → ATP + H:0 AG,' = -43 kJ/mol AG.' =+30.5 kJ/mol at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM. (R= 8.315 JK' mol"') (ii) Calculate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD The half- reactions are: Acetaldehyde + 2H + 2e + Ethanol NAD + 2H + 2e + E"= - 0.20V NADH + H- E°"= - 0.32V (F= 96.485 kJ/V/mol)
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