(II) A boat, whose speed in still water is 2.50 m/s, must cross a 285-m-wide river and arrive at a point 118 m upstream from where it starts (Fig. 3–45). To do so, the pilot must head the boat at a 45.0° upstream angle. What is the speed of the river's current? +118 m→ Finish River `current 285 m 45.0° FIGURE 3-45 Start Problem 48. Path of boat

(II) A boat, whose speed in still water is 2.50 m/s, must cross a 285-m-wide river and arrive at a point 118 m upstream from where it starts (Fig. 3–45). To do so, the pilot must head the boat at a 45.0° upstream angle. What is the speed of the river's current? +118 m→ Finish River `current 285 m 45.0° FIGURE 3-45 Start Problem 48. Path of boat

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

#7
Which of the following will lead to the greatest increase in the acceleration in the x- direction? Select one: O a. Decrease magnitude of a; Decrease angle of a from the x- axis b. Increase magnitude of a; Increases angle of a from the x- axis c. Decrease magnitude of a; Increase angle of a from the x- axis O d. Increase magnitude of a; Decrease angle of a from the x- axis Clear my choice
39 - A boat on the shore wants to cross the 20 m wide river perpendicular to the current at 4 m / sec. Since the current velocity is 3 m / sec, how far from the point it wants to reach the shore?A) 25B) 5C) 20D) 15E) 10
5) A baseball is thrown horizontally off a very tall building with an initial velocity of 17.5 m/s. Find the ball’s horizontal and vertical positions and velocities after 2.4 seconds have passed
2-4
2-5
#5
A football is kicked from ground level with an initial velocity of 20 4 m/s at angle of 32.5 above the horizontal. How long, is seconds, is the football in the air before it hits the ground? Ignore air resistance Bubet Answer
Question 1 When a projectile is at its' maximum height: O The vertical component of velocity is zero O The vertical position is zero The acceleration is zero O The horizontal component of velocity is zero Question 2
The time it takes for a projectile to go up to its' maximum height is the same amount of time that the projectile takes to fall from its' maximum height back down to its initial height. True False
Vo = 65.0 m/s 35.0° h =115 m FIGURE 3-51 Problem 59. A ball is launched at an angle of 35.0° off a 115 meter high cliff with an initial velocity of 65.0 m/s. If friction is negligible, how far from the base of the cliff does the ball land? Use the equations of motion to determine the answer. Give your answer in meters to the correct number of significant figures.
3-32 Deterire the agnitutde and diretiun angle 9 uf force Fa so that the particle shawm in Fig. P1-12 is in oqui- Jibrium. к -м 33 = 80 N Fie. P3-12