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Ignoring friction, If an equal force is applied to a 1 kg box and a 10 kg box, the acceleration of V [ Select ] the of the 10 kg box is the acceleration of the 1 kg box. same as 1/10 100 times 10 times

Ignoring friction, If an equal force is applied to a 1 kg box and a 10 kg box, the acceleration of V [ Select ] the of the 10 kg box is the acceleration of the 1 kg box. same as 1/10 100 times 10 times

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Concept: Comparing Accelerations with Equal Force** Ignoring friction, if an equal force is applied to a 1 kg box and a 10 kg box, the acceleration of the 10 kg box is [Select] the acceleration of the 1 kg box. **Options:** - same as - 1/10 - 100 times - 10 times **Explanation:** This scenario involves the application of Newton's Second Law of Motion, which states that force is equal to mass times acceleration (F = ma). Given that the force is the same for both boxes: 1. The acceleration of the 1 kg box can be calculated as F = 1 kg * a₁. 2. The acceleration of the 10 kg box can be calculated as F = 10 kg * a₂. Since the forces are equal, the relationship between accelerations can be expressed as a₂ = a₁ / 10, meaning the acceleration of the 10 kg box is 1/10 of the acceleration of the 1 kg box.
Transcribed Image Text:**Physics Concept: Comparing Accelerations with Equal Force** Ignoring friction, if an equal force is applied to a 1 kg box and a 10 kg box, the acceleration of the 10 kg box is [Select] the acceleration of the 1 kg box. **Options:** - same as - 1/10 - 100 times - 10 times **Explanation:** This scenario involves the application of Newton's Second Law of Motion, which states that force is equal to mass times acceleration (F = ma). Given that the force is the same for both boxes: 1. The acceleration of the 1 kg box can be calculated as F = 1 kg * a₁. 2. The acceleration of the 10 kg box can be calculated as F = 10 kg * a₂. Since the forces are equal, the relationship between accelerations can be expressed as a₂ = a₁ / 10, meaning the acceleration of the 10 kg box is 1/10 of the acceleration of the 1 kg box.
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