If your product had not been dry, would the yield be higher or lower than the yield based on a dry product? Explain your choice. 2. How many grams of alum can be obtained from 25.0 g of aluminum when the reaction proceeds with 100% yield? How many grams of alum would be obtained if the reaction were to proceed with 75.0% yield? 3. Why was excess KOH used? 4. Explain why boiling the alum solution would help induce crystal formation.
If your product had not been dry, would the yield be higher or lower than the yield based on a dry product? Explain your choice. 2. How many grams of alum can be obtained from 25.0 g of aluminum when the reaction proceeds with 100% yield? How many grams of alum would be obtained if the reaction were to proceed with 75.0% yield? 3. Why was excess KOH used? 4. Explain why boiling the alum solution would help induce crystal formation.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. If your product had not been dry, would the yield be higher or lower than the yield based on a dry product? Explain your choice.
2. How many grams of alum can be obtained from 25.0 g of aluminum when the reaction proceeds with 100% yield? How many grams of alum would be obtained if the reaction were to proceed with 75.0% yield?
3. Why was excess KOH used?
4. Explain why boiling the alum solution would help induce crystal formation.
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